H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
Answer:
sorry
Step-by-step explanation:
sorry i dont know the answer because i read in class 2
i am very sorry
okay so first you wanna turn that 120% into a decimal and the decimal form of that would be 1.2 or 1.20
Secondly you want to multiply 875 by the 1.2
875*1.2 = 1050
So if they sell 120% of last years sales they will sell 1050 cars this year.
Hope this helped :)
Answer:
Therefore the height of the water in the pool changes at the rate of 
feet per minute.
Step-by-step explanation:
Given that the shape of swimming pool is right circular cylinder.
The rate of water pouring in the pool = 3 cubic feet per minute.
It means the rate of change of volume is 3 cubic feet per minute.
cubic feet per minute.
When the volume of the swimming pool changed it means the height of the water level of the pool change and the radius of the swimming pool remains constant.
Let the height of the pool be h.
The volume of the pool is = 
cubic feet
cubic feet
Therefore,
v
Differentiating with respect to t
Putting
The change of height of the pool does not depend on the depth of the pool.
Therefore the rate of change of height of the water in the pool is feet per minute.
Answer:
Purple, yours?
Step-by-step explanation:
