Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype 
. A normal man will have the genotype 
. When the 2 marries:
x = 
It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x 
= 
50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
Answer:An amoeba uses asexual reproduction to reproduce using a process of binary fission.
Well the picture could help :)
The virus attaches itself to a specific host cell (the cell in which it will reproduce) the virus injects its genetic material into the host cell. the host cell uses the genetic material to make new viruses. the host cell splits open, releasing the viruses.
Black or speckled. Also, it depends if the traits can exist in co-dominance or incomplete dominance. Be sure to check my answer :))
