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3 years ago

Jerome solved the equation 1

Mathematics

2 answers:

inn [45]3 years ago

6 0

Answer:

B (second option)

Step-by-step step 2, the LCD was not used correctly to make equivalent fractions.

Ad libitum [116K]3 years ago

4 0

Answer:

the answer is b

Step-by-step explanation:

got it right

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The length of a rectangular garden is 6 feet less than 3 times its width. the area is 360 square feet. what is the length of the

aleksandr82 [10.1K]

$l = 3w-6
\\A = l*w
\\A = (3w-6)(w)
\\360 = (3w-6)(w)
\\ 360 = 3w^2 - 6w
\\ 0 = 3w^2-6w-360
\\ 3(w^2-2w-120) = 0
\\ 3(w+10)(w-12) = 0
\\ w = 12 
\\ 12*3 = 36 -6 = 30
\\ l = 30$

6 0

4 years ago

Hi! Can anyone answer this? Please! <br><br><br>Solve the inequality. <br>13>-2/3-3

horsena [70]

Answer:The left side 13 is greater than right side -3.6 which means statement is true

3 0

4 years ago

Read 2 more answers

The gasoline consumption of a bus is 30l/100km and of a car is 9l/100km. To go on a 250 km trip, 30 people can either go by car

shutvik [7]

Answer:

The bus will take less consumption and by 60 litre

4 0

3 years ago

Una caja de fideos de 7.2 onzas a 0.67 o una caja de fideos de 13 onzas a 1.28 cual tiene el mejor precio

uysha [10]

Answer:

The first one. Brainly is also in spanish

4 0

3 years ago

A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

marin [14]

Answer:

$Range = 85$

$\sigma = 28.71$

$Interval = [666.78, 781.62]$

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

$Range = Highest - Least$

From the dataset:

$Highest = 772$

$Least = 687$

So:

$Range = Highest - Least$

$Range = 772-687$

$Range = 85$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

First, calculate the mean

$\bar x = \frac{769 +691 +............+715}{25}$

$\bar x = \frac{18105}{25}$

$\bar x = 724.2$

So, the standard deviation is:

$\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}$

$\sigma = \sqrt{\frac{20604}{25}}$

$\sigma = \sqrt{824.16}$

$\sigma = 28.71$

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

$Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]$

$Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]$

$Interval = [666.78, 781.62]$

4 0

3 years ago