Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
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Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
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Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
10 knots. 5 knots above and 5 knots below are added to equal 10 knots.
Answer:
40 min is the answer
Step-by-step explanation:
To solve this we need to convert all the units into SI units
for ritu,
speed= 90km/hr
= 90 × 1km/ 1hour
= 90×1000/3600 m/s
= 25m/s
distance = 120×1000m
time = distance/ speed
= 120000/25
= 4800sec
= 4800/60min
= 80 min
for garima,
distance =120×1000m
speed = 60km/hr
= 60×1000/3600 m/s
=100/6 m/
time = 120000/(100÷6)
= 7200sec
= 7200÷60 min
= 120 min
time difference is 120-80 = 40 min
Answer:
the point through which it passes i.e (1,5)
Answer:
1200 ounces
Step-by-step explanation:
How much of an alloy that is 10% copper should be mixed with 600 ounce of an alloy that is 70%copper in order to get an alloy that is 30%copper?
Let us represent
Number of ounce of 10% copper = x
Hence, our Equation =
x × 10% + 600 × 70% = (x + 600) × 30%
0.1x + 420 = (x + 600)0.3
0.1x + 420 = 0.3x + 180
Collect like terms
0.3x - 0.1x = 420 - 180
0.2x = 240
x = 240/0.2
x = 1200 ounces
