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zimovet [89]
3 years ago
9

A={b,l,o,u,s,e} and U={a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z}.

Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0

Answer:

oof

Step-by-step explanation:

Klio2033 [76]3 years ago
3 0

Blouse

The Alphabet

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WHAT ARE THE EXCLUDED VALUES?
hichkok12 [17]
Since the denominator cannot be zero, you can set 4z+1=0 to find the excluded values. 
4z+1=0
4z=-1
z=-1/4
And thus, z cannot equal -1/4
5 0
3 years ago
Consider this expression.
Harlamova29_29 [7]

Answer:

= -30x -36

Step-by-step explanation:

-3x . 2-24x - 36= -30x - 36

-3x . 2 -24x - 36

= -6x - 24x - 36

= -30x - 36

8 0
3 years ago
The results of a standardized test are normally distributed. The mean test score is 312. Of the scores, 16% are under 307. What
amid [387]

Answer:

the answer is B five

Step-by-step explanation:

three hundred and seven minus three hundred and twelve

4 0
2 years ago
The polynomial x 3 + 5x 2 - ­57x -­189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. If t
Ipatiy [6.2K]
V=x^3+5x^2-57x-189
Width: W=(x+3) in = 15 in →x+3=15
Solving for x:
x+3-3=15-3→x=12

With x=12 the Volume would be:
V=(12)^3+5(12)^2-57(12)-189
V=1,728+5(144)-684-189
V=1,728+720-684-189
V=1,575

V=W*D*H
Depth: D
Height: H
with H>D

V=1,575; W=15
Replacing in the equation above:
1,575=15*D*H
Dividing both sides by 15
1,575/15=(12*D*H)/15
105=D*H
3*5*7=D*H
D<H
If D=5→H=3*7→H=21
If D=7→H=3*5→H=15

Answer: Option <span>C. height: 21 in. depth: 5 in.
</span>
Please, see the attached file for another form to solve the problem

4 0
3 years ago
Read 2 more answers
Just look at the picture it doesn’t have words
dimulka [17.4K]

Answer: c 6

Step-by-step explanation:

3 2/3 +2.3...

2.3....=2 1/3

3 2/3 + 2 1/3= 5 3/2

=6

7 0
3 years ago
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