A={b,l,o,u,s,e} and U={a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z}.
2 answers:
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Answer:
Step-by-step explanation:
we know that
The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial
In this problem we have that
The polynomial has roots 1 and (1+i)
so
by the conjugate root theorem
(1-i) is also a root of the polynomial
therefore
The lowest degree of the polynomial is 3
so
Remember that
The leading coefficient is 1
so
a=1
