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nevsk [136]
2 years ago
14

Are 3k3 and 8k like terms?

Mathematics
1 answer:
givi [52]2 years ago
7 0

Answer:

i believe so, 3k3 is just 3k to the third power so i think theyd be like terms still

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Jasmine wants to build a 2 2/5 meter long garden path paved with square stones that measure 1/4 meter on each side. There will b
Allisa [31]
The answer is 9 3/5
3 0
3 years ago
Please help, will grant brainliest if correct, need now!!
Mama L [17]

Answer:

- 7

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 5, - 2 ]

f(b) = f(- 2) = (- 2)² - 4 = 4 - 4 = 0

f(a) = f(- 5) = (- 5)² - 4 = 25 - 4 = 21, thus

average rate of change = \frac{0-21}{-2-(-5)} = \frac{-21}{3} = - 7

3 0
3 years ago
Aaron’s mother purchases a new computer for $1750. If she claims a linear depreciation (loss of value) on the computer at a rate
kirill [66]

After 8 years the value of the computer to be $0 if the Aaron’s mother purchases a new computer for $1750.

<h3>What is a sequence?</h3>

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have:

Aaron’s mother purchases a new computer for $1750. If she claims a linear depreciation (loss of value) on the computer at a rate of $250 per year.

The above problem can be solved using concept of arithmetic sequence

The starting value = $1750

After one year = 1750 - 250 = $1500

After second year = 1500 - 250 = $1250

Common difference = 1500 - 1750 = -250

a(n) = 1750 + (n - 1)(-250)

a(n) = 0  (final value is zero given)

0 = 1750 + (n - 1)(-250)

n - 1 = 7

n = 8 years

Thus, after 8 years the value of the computer to be $0 if the Aaron’s mother purchases a new computer for $1750.

Learn more about the sequence here:

brainly.com/question/21961097

#SPJ1

4 0
1 year ago
A car used 1/ 64 of a gallon of gas to drive 1 4of a mile. At this rate, how many miles can the car travel using 1 gallon of gas
Dovator [93]

Answer: 16 miles

Step-by-step explanation:

The car used 1/64 gallons to travel 1/4 miles. To find out how many miles the car can travel using 1 gallon, use direct proportion:

1/64 gallons            :              1/4 miles

1 gallon                   :                  x miles

Cross multiply:

1/64x = 1/4

x = 1/4 ÷ 1/64

= 1/4 * 64/1

= 16 miles

On one gallon of gas, the car can travel 16 miles.

5 0
3 years ago
Which of the following is a radical equation
Luden [163]
Its b because yeah im just kidding idk im really stupid jk its b hahaha 

3 0
2 years ago
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