<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
the solution is (2, -6)
Step-by-step explanation:
Substitute the second equation into the first, replacing y in the first:
2x - (-4x+2) = 10
Simplifying, we get:
2x + 4x - 2 = 10, or:
6x = 12, which yields x = 2.
Substituting 2 for x in the second equation yields y = -4(2) + 2 = 0, or y = -6
Then the solution is (2, -6).
m=18 when r = 2.
Step-by-step explanation:
Given,
m∝
So,
m = k×,--------eq 1, here k is the constant.
To find the value of m when r = 2
At first we need to find the value of k
Solution
Now,
Putting the values of m=9 and r = 4 in eq 1 we get,
9 = 
or, k = 36
So, eq 1 can be written as m= 
Now, we put r =2
m = 
or, m= 18
Hence,
m=18 when r = 2.
Y=180-111=69
x=360-123-70-69=98
That's your answer.
Simplify the following:4^5/4^4
Combine powers. 4^5/4^4 = 4^(5 - 4):4^(5 - 4)
5 - 4 = 1:Answer: 4
