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Olin [163]
3 years ago
7

There are 16 types of flowers used to decorate for a party. Twelve of the flowers types last an average of 4 days before they wi

lt. The remaining flowers last an average of 6 days.
What is the average number of days before the flowers wilt?
Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer: The average number of days before the flowers wilt is 5 days .

Step-by-step explanation:

Since we have given that

Total number of flowers used to decorate for a party = 16

Number of days 12 of the flowers types last = 4 days

Number of days 4 of the flowers types last = 6 days

Since there are only 2 types of flowers that were group into.

We need to find the average number of days before the flowers wilt is given by

=\frac{4+6}{2}\\\\=\frac{10}{2}\\\\=5

Hence, the average number of days before the flowers wilt is 5 days .

Vlad [161]3 years ago
5 0
16 - 12 = 4 flowers
4f = 6 days
1 flower = 1.5 days

1.5 × 16 = 24 days
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Please help me <br> 30 points <br> Show you work
GenaCL600 [577]

Answer:

(a) A translation is a rigid transformation. How does this statement support line s being parallel to line r?

Because ALL of the points of line r move the same distance in the same direction, then the inclination of the line s doesn't change with respect line r.

(b) Write and expression for the slope of line r:

(k-n)/(j-m)

(c) Write and expression for the slope of line s:

(k-n)/(j-m)

(d) Line q is a vertical is a vertical translation of line s 3 units down. P'' is the image of P'. What are the coordinates of P''?

The coordinates of P'' are:

P''=(m,n+ϴ-3)

Step-by-step explanation:

(a) A translation is a rigid transformation. How does this statement support line s being parallel to line r?

Because ALL of the points of line r move the same distance in the same direction, then the inclination of the line s doesn't change with respect line r.


(b) Write and expression for the slope of line r.

Line r goes through the points:

P=(m,n)=(xp,yp)→xp=m, yp=n

Q=(j,k)=(xq,yq)→xq=j, yq=k

Slope of line r is:

mr=(yq-yp)/(xq-xp)

Replacing the coordinates, the expression for the slope of line r is:

mr=(k-n)/(j-m)


(c) Write and expression for the slope of line s.

Line s goes through the points:

P'=(m,n+ϴ)=(xp',yp')→xp'=m, yp'=n+ϴ

Q'=(j,k+ϴ)=(xq',yq')→xq'=j, yq'=k+ϴ

Slope of line s is:

ms=(yq'-yp')/(xq'-xp')

Replacing the coordinates, the expression for the slope of line s is:

ms=[(k+ϴ)-(n+ϴ)]/(j-m)

Eliminating the parentheses in the numerator:

ms=[k+ϴ-n-ϴ]/(j-m)

Simplifyng:

ms=(k-n)/(j-m)


(d) Line q is a vertical is a vertical translation of line s 3 units down. P'' is the image of P'. What are the coordinates of P''?

3 units down, then change only the ordinate y:

P''=(xp',yp'-3)

Replacing xp' and yp':

P''=(m,n+ϴ-3)


7 0
3 years ago
Read 2 more answers
The radius of a semicircle is 4 miles. What is the semicircle's area?
adell [148]

Answer:

8\pi miles or 25.133 miles

Step-by-step explanation:

your radius is 4 miles.

The area of a circle is A= \pi r^{2}

Therefore, the area of this circle is 4^{2} \pi, or 16\pi

Half of this area, because what you're looking for is a semi-circle, is:

8\pi (exact) or 25.133 (rounded) miles.

6 0
2 years ago
Please help me with this question!
Alina [70]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°, thus

∠1 = 180° - (72 + 57)° = 180° - 129° = 51°

The right angle at the left vertex is composed of 72° and ∠2, thus

∠2 = 90° - 72° = 18°

57° and ∠3 form a straight angle and are supplementary, thus

∠3 = 180° - 57° = 123°

∠4 = 180° - (∠2 + ∠3 ) ← sum of angles in a triangle

∠4 = 180° - (18 + 123)° = 180° - 141° = 39°

4 0
3 years ago
I need help with these two answers please :/
4vir4ik [10]
Rise over run is -2/4 or simplified as -1/2
The second one is
\frac{1 - 3}{4 - 0}  =  \frac{ - 2}{4}

7 0
3 years ago
How do I graph y=2x if there is only slope
lord [1]
There is an invisible +0 at the end. this means the y intercept is 0
3 0
3 years ago
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