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3 years ago

37 % of $2927 is what

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

Answer:

1082.99

Step-by-step explanation:

2927 - 100%;

x - 37%;

=> x = (37*2927)/100 = 1082.99

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What is 8/35 pls help me

Rus_ich [418]

As a decimal it is 0.2285714
THE NUMBERS AFTER THE DECIMAL NEED A LINE OVER THEM. They keep repeating themselves. Have a good one babes.

6 0

2 years ago

Kylie is planning to provide online science and Chinese language tutoring sessions. The sciences

Ivahew [28]

Answer:

120 ≤ 20c + 40s

Step-by-step explanation:

(Assuming her name is Kylie, who is giving 40 minute science sessions and 20 minute Chinese sessions.)

The unit for time will be minutes.

Write an equation for time needed for science sessions

40s = t

Write an equation for time needed for Chinese sessions

20c = t

Combine the two equations for the total time.

20c + 40s = total time

She does not want the total time to be more than two hours.

Convert two hours to minutes. There are 60 minutes in an hour.

2h * 60mins = 120 mins

Therefore t ≤ 120. Include this into the equation.

120 ≤ 20c + 40s

8 0

2 years ago

Nate's savings account for the business had $12.10 more at the end of the year than the $252 it had at the begining of the year.

Ulleksa [173]

4.58% is the answer. You need to add the $12.10 to $252 to get the total. 252x100%=2500÷264.10 then subtract the answer from 100.

8 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

2 years ago

ASAP WHO EVER ANSWER THIS QUESTION WILL BE MARKED BRANLIEST URGENT

Yuliya22 [10]

Answer:

i think its A. . .

Step-by-step explanation:

6 0

2 years ago