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lozanna [386]
3 years ago
10

The graph of the relation T is shown below.

Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

The sets of the domain and the range of T are, respectively:

Dom \{T\} =\{-3,0,3\}

Ran\{T\} = \{-4.-3,2,3\}

Step-by-step explanation:

The values of the relation T that belongs to the domains correspond with the values on the x-axis and associated with the given points, whereas the range corresponds with the respective values of the y-axis. Let T = \{(x,y)|(-3,3),(3,2),(0,-3),(3,-4)\}

The sets of the domain and the range of T are, respectively:

Dom \{T\} =\{-3,0,3\}

Ran\{T\} = \{-4.-3,2,3\}

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Your limting the amount of sandbags you have if you take away and when your adding your adding more sandbags.
8 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
PLEASE HELP ME!!  i have to answer this question fast please help
otez555 [7]
Y=-1/4x+7.5 is the right equation
5 0
3 years ago
M is the midpoint of YZ. If YM = x + 3, and YZ = 3x -1, find MZ
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3 0
3 years ago
Solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x < 360°?
Sedbober [7]

Answer:

Step-by-step explanation:

cos (x/2)=cos x+1

cos (x/2)=2cos ²(x/2)

2 cos²(x/2)-cos (x/2)=0

cos (x/2)[2 cos (x/2)-1]=0

cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)

x/2=2nπ+π/2,2nπ+3π/2

x=4nπ+π,4nπ+3π

n=0,1,2,...

x=π,3π

or x=180°,540°,...

180°∈[0,360]

so x=180°

or

2cos(x/2)-1=0

cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)

x/2=360n+60,360n+300

x=720n+120,720n+300

n=0,1,2,...

x=120,300,840,1020,...

only 120° and 300° ∈[0,360°]

Hence x=120°,180°,300°

7 0
2 years ago
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