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kkurt [141]
2 years ago
13

Data will be collected on the following variables. Which variable is most likely to be approximated by a normal model?

Mathematics
1 answer:
brilliants [131]2 years ago
4 0
You forgot to add some information
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What is 5 times 1863636373726
sashaice [31]
<span>9.3181819e+12v is the answer</span>
5 0
3 years ago
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Multiply the polynomials (5x^2+4x-4)(4x^3-2x+6)<br> Explain your steps!!
Lapatulllka [165]
So distribute using distributive property
a(b+c)=ab+ac so

split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24

the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24




4 0
3 years ago
Can someone help lol free points btw
vazorg [7]

Answer:

The correct answer would be C

Step-by-step explanation:

Looking at the data, you can tell that the first two are going to be wrong. The minimum is 1, and the maximum is 5.

A mode, by definition, is the number that appears most in the data. According to answer D, 3 appears 3 times in the data. That is incorrect, as 3 only appears twice in the data.

This leaves only answer C. We need to make sure it's correct. The answer mentions the mean as a value between 2 and 3. Mean is the average. To find the average, you must add all the values together first.

1 + 2 + 5 + 3 + 2 + 2 + 5 + 3 = 23

Then, you must divide the value by the number of data given. There are 8 numbers here, so you must divide 23 by 8.

23/8 = 2.875

2.875 is between the numbers 2 and 3 like answer C said, so C is correct.

3 0
3 years ago
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A packaging company is planning is in the planning stages of creating a box that include a three dimensional support inside the
Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

                                       width = 5 feet

                                       height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

x^{2} = 6^{2} + 5^{2}

x^{2} = 36 + 25

   = 61

x = \sqrt{61}

  = 7.81

let the length of the diagonal support be represented by l. So that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

l^{2} = x^{2} + 8^{2}

  = \sqrt{61} + 64

l  = \sqrt{\sqrt{61} + 64 }

  = 61 + 8

  = 69

Thus, the length of the diagonal support is 69 feet.

6 0
3 years ago
A circle has a radius of 63 cm.
Montano1993 [528]
Arc length = radius * central angle (in radians)
arc length = 63 * 2PI/9 radians
arc length = 14 PI

4 0
4 years ago
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