<span>let length of painting = L
and width = W
from area = length times width
180 inch^2 = L times W
but L = 5/4 times W
180 inch^2 = 5/4 times W times W
W^2 = (4 x 180)/5
W = 12
but L = 5/4 x W
L = 5/4 x 12
L = 15
</span>
<span>Answer: The dimensions of the painting are </span><u>12 x 15 inches</u>.
Answer:
5.1
Step-by-step explanation:
Before we calculate the y value for the point Q that is located two thirds the distance from point P to point R, we need to get the distance of point p from point R using the formula for calculatingf the distance between two points
D = √(x2-x1)²+(y2-y1)²
Given P(−2, 7), and R(1, 0)
RP = √(1-(-2))²+(0-7)²
RP = √3²+(-7)²
RP = √9+49
RP =√58
To get the y value for point Q that is located two thirds the distance from point P to point R, this will give
PQ = y = 2/3 of √58
= 5.1
Answer:
B. 32
Step-by-step explanation:
There are 8 fl. oz. in one cup
8*4=32
Answer:
D = 59t
P = 42t
5 hours after noon, darmian is 17 miles closer to the stadium than paisley
Step-by-step explanation:
At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.
Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.
At t hours after noon, their distance covered will be;
Damian; D = 59t
Paisley; P = 42t
This is because distance = speed × time
Now, 5 hours after noon, their respective distance covered will be;
D(5) = 59 × 5 = 295 miles
P(5) = 42 × 5 = 210 miles
This means that;
distance of Damian from the stadium is; 383 - 295 = 88 miles
Distance of paisley from the stadium is;
315 - 210 = 105 miles
Difference in their distances to the stadium = 105 - 88 = 17 miles
Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley
This is a proportion problem because the problem stated that the two team pennants are similar.
Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base = 6 in ; length = x ?
9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x
The length of the side of the smaller pennant is 3 inches.
