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3 years ago

Ugh I feel bad asking for so much help, but answer choices are listed!

Mathematics

1 answer:

Archy [21]3 years ago

6 0

Answer:

Pretty sure b is the correct one

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Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at $(x_1,y_1)$ and point Q at $(x_2,y_2)$ in the proportion a:b, we use the formula:

$x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1$

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

$x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1$

4 0

4 years ago

What is the missing angle in the right triangle?

Ainat [17]

Answer:

Step-by-step explanation:

For angle A, 3 is the adjacent leg. 8 is the hypotenuse.

The trig ratio that relates the adjacent leg to the hypotenuse is the cosine.

$\cos A = \dfrac{adj}{hyp}$

$\cos A = \dfrac{3}{8}$

$\cos A = 0.375$

We know the cosine of angle A equals 0.375. We take the inverse cosine of 0.375 to find the measure of the angle.

$A = \cos^{-1} 0.375$

$A = 68^\circ$

8 0

3 years ago

6^x+8=17^2x-2 can I have help

bazaltina [42]

$6^{x+8}=17^{2x-2}\ \ \ \ \ \ |both\ sides\ log_6\\\\log_66^{x+8}=log_617^{2x-2}\\\\x+8=(2x-2)log_617\\\\x+8=2xlog_617-2log_617\\\\x-2xlog_617=-2log_617-8\\\\x(1-2log_617)=-2log_617-8\ \ \ \ |divide\ both\ sides\ by\ (1-2log_617)\\\\x=\frac{-2log_617-8}{1-2log_617}\\\\x=\frac{-(log_617^2+8)}{-(log_617^2-1)}\\\\x=\frac{log_6289+8}{log_6289-1}$

7 0

4 years ago

Please help me with this question

mash [69]

Answer:

angle AOD = 90⁰

BOD = 3x⁰

90⁰+3x⁰ = 180⁰( being straight angle)

3x = 180⁰-90⁰

3x = 90⁰

x = 90⁰/3

x = 30⁰

now

y⁰+139⁰ = 180⁰(being straight angle)

y⁰ = 180⁰-139⁰

y⁰ = 41⁰

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula

dsp73

<h3>Solution:</h3>

$( \sqrt{2} + 1)(5 + \sqrt{2}) \\ = \sqrt{2} (5 + \sqrt{2} ) + 1(5 + \sqrt{2} ) \\ = 5 \sqrt{2} + 2 + 5 + \sqrt{2} \\ = 7 + 6 \sqrt{2}$

<h3>Answer:</h3>

7 + 6√2

5 0

3 years ago

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