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Dvinal [7]
2 years ago
10

the value of a machine depreciates at the rate of 20% p. a. compound depreciation find the total compound depreciation after 3 y

rs if the present value is Rs. 175000​
Business
1 answer:
Stella [2.4K]2 years ago
7 0

Answer:

R 85400

Explanation:

The amount of depreciation will be the current amount minus the amount after three years.

amount after threes is calculated as follow

A= P x( 1+ r) ^n

Wheres A: amount after 3 years

P : principal amount =r 175,000; r = -20%, n is number of period

A = 175,000 x ( 1- 0.2)^3

A =175,000 x(0.8)^3

A = 175,000 x 0.512

A=89,600

Depreciation =175,000 - 89,600

=R 85400

You might be interested in
A process control system costs $200,000, has a three year service life, and a salvage value of $20,000. Find the depreciation an
Advocard [28]

Answer:

A.

Depreciation expense each of the three years would be $60,000

Book value at the end of year 1 = $140,000

Book value at the end of year 2 =$80,000

Book value at the end of year 3 =  $20,000

B.

Depreciation expense in year 1 =$90,000

Depreciation expense in year 2 =$60,000

Depreciation expense in year 3 =$30,000

Book value at the end of year 1 =$110,000

Book value at the end of year 2 = $50,000

Book value at the end of year 3 =  $20,000

C.

Depreciation expense in year 1 = $133,333.33

Book value at the end of year 1 = $66,666.67

Depreciation expense in year 2 =  $44,444.45

Book value at the end of year 2 = $22,222.22

Depreciation expense in year 3 = $14,814.16

Book value at the end of year 3 = $7,407.40

Explanation:

Straight line depreciation expense = (Cost of asset - Salvage value) / useful life

($200,000 - $20,000) / 3 = $60,000

Depreciation expense each of the three years would be $60,000

Book value at the end of year 1 = $200,000 - $60,000 = $140,000

Book value at the end of year 2 =  $140,000 - $60,000 = $80,000

Book value at the end of year 3 = $80,000 - $60,000 = $20,000

Sum-of-the-year digits = (remaining useful life / sum of the years ) x  (Cost of asset - Salvage value)

Sum of the years = 1 + 2 + 3 = 6 years

Depreciation expense in year 1 = (3/6) x ($200,000 - $20,000) = $90,000

Depreciation expense in year 2 = (2/6) x ($200,000 - $20,000) = $60,000

Depreciation expense in year 3 = (1/6) x ($200,000 - $20,000) = $30,000

Book value at the end of year 1 = $200,000 - $90,000 = $110,000

Book value at the end of year 2 = $110,000 - $60,000 = $50,000

Book value at the end of year 3 = $50,000 - $30,000 = $20,000

Depreciation expense using the double declining method = Depreciation factor x cost of the asset

Depreciation factor = 2 x (1/useful life) = 2/3

Depreciation expense in year 1 = (2/3) x $200,000 = $133,333.33

Book value at the end of year 1 = $200,000 - $133,333.33 = $66,666.67

Depreciation expense in year 2 = (2/3) x $66,666.67 = $44,444.45

Book value at the end of year 2 = $66,666.67 - $44,444.45= $22,222.22

Depreciation expense in year 3 = (2/3) x$22,222.22 = $14,814.16

Book value at the end of year 3 =$22,222.22 - $14,814.16 = $7,407.40

4 0
2 years ago
. George worked 52 hours last week. In his job, any hour past 40 hours is considered overtime. His overtime pay is 1.5 times his
stiks02 [169]
Find how much time he worked overtime.
52-40=12
Find his overtime salary.
22.5*1.5=33.75
Calculate how much money he makes for 40 hours.
40*22.5=900
Calculate how much money he made in overtime.
33.75*12=405
Add both earnings together.
900+405=1305

George earned 1305$ last week.
3 0
3 years ago
Inthe 1920's, the value of the German mark fell dramatically. in June 1922, a U.S. dollar could buy 320 marks; by December of th
muminat

Answer:

The answer is C: Hyperinflation

Explanation:

Hyperinflation is high and accelerating form of inflation. It results in quick decline of the local currency`s real value. It also leads to increased prices of all goods and consumables

From the data,

In June 1922, 1 german Mark was equal to 0.003125 USD (1/320)

Whereas in December, 1922, the same german Mark was equal to 0.000125 USD. (1/8000)

5 0
3 years ago
The following December 31, 2021, fiscal year-end account balance information is available for the Stone Corporation:Cash and cas
blsea [12.9K]

Answer:

1.

Total current assets  = $112500

2.

Short term investments = $2300

3.

Retained earnings = $15500

Explanation:

1.

The total current assets can be determined using the current ratio provided for 2021. The current ratio is calculated by dividing the value of total current assets by the value of the total current liabilities.

1.5  =  Total current assets / (51000 + 23000 + 1000)

1.5 = Total current assets / 75000

1.5 * 75000 = Total current assets

Total current assets  = $112500

2.

Short term investments are a part of the current assets. The value of short term investments is,

112500 = 6200 + 32000 + 72000 + Short term investments

112500 = 110200 + Short term investments

112500 - 110200 = Short term investments

Short term investments = $2300

3.

The basic accounting equation states that the total assets is always equal to the value of total liabilities plus total equity.

Total assets = Total Liabilities + Total Equity

(112500 + 180000) = [(51000 + 23000 + 1000) + 42000]  +  (160000 + Retained earnings)

292500 = 117000 + 160000 + Retained earnings

Retained earnings = 292500 - 277000

Retained earnings = $15500

6 0
3 years ago
You are planning to save for retirement over the next 25 years. To do this, you will invest $820 per month in a stock account an
alina1380 [7]

Answer:

The withdraw amount is "11,227.42".

Explanation:

The given values are:

In stock account,

PMT = $820

Interest rate = \frac{10.2 \ percent}{12}

N = 300

PV = 0

In Bond account,

PMT = $420

Interest rate = \frac{6.2 \ percent}{12}

N = 300

PV = 0

Now,

By using the FV (Future value) function, the value in Stock account will be:

= FV(rate,nper,pmt,[pv],[type])

= 1,125,795.30

By using the FV (Future value) function, the value in Stock account will be:

= FV(rate,nper,pmt,[pv],[type])

= 300,181.3321

After 25 years,

The value throughout the account, will be:

= 300,181.3321 + 1,125,795.30

= 1,425,976.63

By using the PMT function, we can find the with drawling amount. The amount will be:

= PMT(rate, nper, pv, [fv], [type])

= 11,227.42

4 0
2 years ago
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