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GaryK [48]
3 years ago
12

In which area is composing for games different from composing for movies?

Computers and Technology
1 answer:
kondaur [170]3 years ago
8 0

Answer: royalties earned

Explanation:

In areas such as the looping scores, temp tracks and adaptive scores, there are similarities when composing for games and when composing for movies.

The area where there is difference when composing for games and composing for movies is the royalties earned. The interest that is earned on royalties for both cases are different.

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You are purchasing a new printer. Which of the following is the most important requirement?
OlgaM077 [116]

Question↓

You are purchasing a new printer. Which of the following is the most important requirement?

Answer↓

A. Is the printer compatible with your computer's operating system?

If The Printer is Not Compatible With your Computer you will not Be able to Use Therefore, you Will have to buy a New One.

xXxAnimexXx

Hope this Helps! ^ω^

7 0
2 years ago
Using Sequential Search on an array of size n, the search key is definitely present in the array. The probability of matching th
MissTica

Answer:

(11n-5) / 12 is correct answer.

Explanation:

The Probability that key will match to nth term = 1/2

The Probability that key will match to n-1th term = 1/3

As all other probabilities are equal

The Total Probability that key matches to any of 1 to n-2 index = 1 - 1/2 - 1/3 = 1/6

The Probability that key matches to any of 1 to n-2 index = (1/6) / n-2 = (1/6)* (n-2))

Let P(i) = Probability that key matches to ith index.

The Average time complexity = 22 i=1 P(i) * i

The Average time complexity = 1/(6(n-2) * ( sum of 1 to n-2 ) + (n-1) / 3 + n/2

The Average time complexity = 1/(6(n-2) * ( n-2)*(n-1) / 2 + ( n-1) / 3 + n/2

The Average time complexity = 1/6 * (n-1)/2 + (n-1)/3 + n/2

The Average time complexity = (n-1)/12 + (n-1)/3 + n/2

The Average time complexity = (n-1 + 4 * n - 4 * 1 +6 * n)/12

The Average time complexity = 11n-5 / 12

so (11n-5) / 12 is correct answer.

7 0
3 years ago
Suppose you have a 16-bit machine with a page size of 16B. Assume that any unsigned 16-bit integer can be a memory address. Also
irinina [24]

Answer:

2^11

Explanation:

Physical Memory Size = 32 KB = 32 x 2^10 B

Virtual Address space = 216 B

Page size is always equal to frame size.

Page size = 16 B. Therefore, Frame size = 16 B

If there is a restriction, the number of bits is calculated like this:  

number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]

where

physical memory size = 32KB  which is the restriction

n bit machine = frame size = 16

Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11

7 0
3 years ago
All slides in a presentation must use the same transition. True or False?
krek1111 [17]
False. you can make different slides have different transitions
7 0
3 years ago
Read 2 more answers
Jensen is a senior developer for Hackers R'Us, a company that helps secure management information systems. Jensen's new task is
Harlamova29_29 [7]

Answer:

b. white-hat hacker

Explanation:

A White-hat Hacker, also known as an Ethical Hacker is an information security specialist, known for performing penetration testing and checks in search for information and communications system's vulnerabilities on demand for his/her clients.

These efforts are meant to find security risks before someone else does, who could cause any kind of damage to the systems or unauthorized access to sensitive information

6 0
3 years ago
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