Hey lol um pls help i don’t get it

What is the vertex of the graph of the function y=-2x^2+16x-15

andrey2020 [161]

<u>X - Vertex</u>
$Vertex = -\frac{b}{2a} \\Vertex = -\frac{16}{2(-2)} \\Vertex = -\frac{16}{-4} \\Vertex = 4$

<u>Y - Vertex</u>
$y = -2x^{2} + 16x - 15 \\y = -2(4)^{2} + 16(4) - 15 \\y = -2(16) + 64 - 15 \\y = -32 + 64 - 15 \\y = 32 - 15 \\y = 17$

Vertex:(4, 17)

8 0

2 years ago

Find an equation for the line with the given properties. Perpendicular to the line 7x - 3y = 68; containing the point (8, -8)

Sever21 [200]

Answer:

$y=\dfrac{-3}{7}x-\dfrac{32}{7}$

Step-by-step explanation:

Given that,

A line 7x - 3y = 68 and containing the point (8, -8).

The equation can be written as :

$-3y=68-7x\\\\y=\dfrac{68}{-3}+\dfrac{7x}{3}\\\\y=\dfrac{7x}{3}+(\dfrac{-68}{3})$

The slope is :7/3

Line is perpendicular so use m = –3/7

$-8=(-\dfrac{3}{7})\times 8+b\\\\-8+\dfrac{3}{7}\times 8=b\\\\b=\dfrac{-32}{7}$

So, required equation is :

$y=\dfrac{-3}{7}x-\dfrac{32}{7}$

6 0

2 years ago

What are some conclusions you can make ably the distribution of the data?

olganol [36]

Answer: you can say that all of the numbers have been evenly spread through the chart

Step-by-step explanation:

6 0

2 years ago

Jose purchased 4/9 pound of peanut and 7/11 pounds of raisins find the total weight of his purchase

azamat

Answer:

The total weight of his purchase is 1.08 pounds

Step-by-step explanation:

To find the total weight of his purchase, we sum the weight of each of his purchases.

He purchased:

4/9 pound of peanut.

7/11 pounds of raisins

Total:

The least common multiple between 9 and 11 is 99.

Then

$\frac{4}{9} + \frac{7}{11} = \frac{11*4 + 9*7}{99} = \frac{107}{99} = 1.08$

The total weight of his purchase is 1.08 pounds

8 0

2 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

B

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

8 0

2 years ago