A teetotum is a spinning top that has an equal probability of landing on each side. The expected value of one

Mathematics

1 answer:

Mashcka [7]2 years ago

7 0

Probabilities are used to determine the chances of events

The true statement is (c) the teetotum could land on the number 10

<h3>How to determine the true statement</h3>

From the question, we understand that the spinning top is divided into 12 equal segments

This means that the possible outcomes of the spin is from 1 to 12

Hence, the true statement is (c) the teetotum could land on the number 10

You might be interested in

6m - 8 = 2 + 9m - 1 Show your work and answer.

Nookie1986 [14]

6m-8 = 2+9m-1

6m-9m = 2+8-1

-3m=9

m = -3

3 0

4 years ago

Can u help me pls they are exponents with multiplication and division

Ronch [10]

When there is a multiplication involving exponents, we need to evaluate the numbers and each variables separately. In this case, we have 5 and 4 as the numbers, and w and h for the variables.

When we multiply 5 and 4 we get:
$5 \times 4 = 20$

For w, we have ${w}^{6}$ , ${w}^{4}$ , $w$ . While we are multiplying the w's, we need to add the exponents together to get the final answer: ${w}^{6} \times {w}^{4} \times w = {w}^{11}$

For h's, there are ${h}^{2}$ , ${h}^{5}$ , ${h}^{4}$ . When we apply the same thing to h's, we get ${h}^{2} \times {h}^{5} \times {h}^{4} = {h}^{11}$

For the final step, we need to write all of these together: $20 \times {w}^{11} \times {h}^{11} \: \: or \: \: 20 {w}^{11} {h}^{11} \: \: or \: \: 20 {(wh)}^{11}$