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True [87]
3 years ago
9

The domain of f(x) is the set of all real values except 7, and the domain of g(x) is the set of all real values except -3. Which

of
the following describes the domain of (gºf)(x)?
1)) all real values except X-3 and the x for which f(x)7
2)) all real values except X-3 and the x for which f(x)=-3
3)) all real values except x 7 and the x for which f(x) 7
4)) all real values except x 7 and the x for which f(x) -3
Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

The option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>

Step-by-step explanation:

As the domain of f(x) is the set of all real values except 7. So it can be written as follows:

              Domain of f(x) = { x ∈ R | x ≠ 7}

As the domain of g(x) is the set of all real values except -3. So it can be written as follows:

              Domain of g(x) = { x ∈ R | x ≠ -3}

It is a common rule that the domain of a composite function (gºf)(x) will be the set of those input x in the domain of f for which f(x) is in the domain of g.

So, the option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>

Keywords:  domain, composite function

Learn more domain and composite functions from brainly.com/question/2073574

#LearnwithBrainly

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This is harder so i put more points
Inessa [10]

Answer:

Sheet metal costs <u>$20</u> per square foot.

Step-by-step explanation:

7.6x - 2.3x = 106

We are finding the value of x.

5.3x = 106

Divide both sides by 5.3.

x = 106 ÷ 5.3

x = 20

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2 years ago
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PLEASE HELP! THANKS! The measures, in degrees, of the 3 angles of a triangle are given by 2x +1, 3x - 3, and 9x. What is the mea
drek231 [11]
So all of the internal angles of a triangle will add up to 180 degrees.  So if we add all of the expressions given and set them equal to 180, we can solve for x, then solve for each angle...

(2x + 1) + (3x - 3) + 9x = 180
2x + 3x + 9x + 1 - 3 = 180
14x - 2 = 180
14x = 182
x = 13

Now we can substitute 13 into each expression to find the value of each angle...

2x + 1 =
2(13) + 1 =
26 + 1 = 27 degrees

3x - 3 =
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39 - 3 = 36 degrees

9x =
9(13) = 117 degrees

So the 3 angles are 27 degrees, 36 degrees, and 117 degrees.

The smallest is 27 degrees

** Note-- I don't see 27 degrees in the answer choices you gave, so I double checked my math (I didn't find any mistakes).  Please check to see that the question is written correctly (pay close attention to plus and minus signs).
7 0
3 years ago
LCM of 4/6 and 4/8????
Svet_ta [14]

Answer:

24 is the LCM of 4,6,8. I think thats what your looking for.

Hope this helps!

Step-by-step explanation:

5 0
2 years ago
What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

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CaHeK987 [17]
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