All categories

3 years ago

In which is the vaule of the 6 ten times the vaule of the 6 in the number 6000

Mathematics

2 answers:

OLEGan [10]3 years ago

6 0

Answer:

Consider matrix A.

What is the inverse of A? Fill in the missing elements in the matrixs.

Step-by-step explanation:

Consider matrix A.

What is the inverse of A? Fill in the missing elements in the matrixs.

gladu [14]3 years ago

4 0

Answer:

Hello! Your answer would be, 600

Step-by-step explanation:

if we start backwards, the value of 6 in 6000 is equal to 1/1000. If you want to find what is 10 times that, multiply 1/1000 with ten and you get 1/100. That is equal to 6/600. The value of 6 is 600.

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

You might be interested in

PLS HELP ME WITH GEOMETRY PLSAND THANK YOU

Alecsey [184]

Answer:

Yes

Step-by-step explanation:

They are equal acute triangles, are congurent. Your welcom

5 0

2 years ago

A coach of a baseball team orders hats for the 12 players on his team. Each hat costs $9.95. The shipping charge for the entire

Ronch [10]

Answer:

124.4

Step-by-step explanation:

12 x 9.95 = 119.4 dollars

119.4+5.00=124.4

The total cost is $124.40.

6 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Abbie has to do 25 math problems tonight. She has completed 40%. How many problems has she completed?

erik [133]

Answer:

Step-by-step explanation:

0.4*25

7 0

3 years ago

What is the input of a transformation?

Semmy [17]

Operations are processes that take in a set of input resources which are used to transform something, or are transformed themselves, into outputs of products and services.

6 0

3 years ago