Answer:
I needed money to buy stuff at the mall with my friends because I didn't want to spend my own... :/ lol
2x + 3y = 13
–6x + 4y = 0
multiply the first equation by 3
6x +9y = 39
then add the 2nd equation to the first
6x +9y = 39
–6x + 4y = 0
-------------------
13y = 39
divide by 13
y =3
now take an equation and solve for x by substituting in y
2x +3y =13
2x +3(3) =13
2x+9 =13
subtract 9 from each side
2x =4
divide by 2
x=2
Answer (2,3)
Choice A
Answer:
x = 3
Step-by-step explanation:
6 <em>+</em><em> </em><em>5</em><em>x</em><em> </em>= 21
<em>5</em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em>
<em>x</em><em> </em><em>=</em><em> </em><em>3</em>
I hope this helps
:)
If the roots of the equation f(x)=0 are -4,-1, 2 and 5, then binomials (x+4), (x+1), (x-2) and (x-5) are factors of needed polynomial.
Thus, the polynomial will have form
where a is real coefficient (positive or negative). This polynomial has degree 4 as needed.
The form of the graph depends on the sign of coefficient a. Attached diagrams show two different cases of possible forms of graphs (first one for positive coefficient a, second one for negative coefficient a).
