Answer:
The answer is D. Vertex at (-7,-9).
Step-by-step explanation:
The equation is in vertex form, so you take the opposite of x and the constant stays the same. So, the opposite of 7 is -7 and -9 stays the same.
Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB
=AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
Log16 4 = 2
log base 16 then the number four then set that equal to 2
-mn^2-5m^2/(5m-2)(m+4n)
if I did it correctly
I hope this helps you
1)
f (2)=2.2^2-3.2-7
f (2)=8-6-7
f (2)= -5
2)
f (2)=2.2^2-3.2+7
f (2)=8-6+7
f (2)=9