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NNADVOKAT [17]
3 years ago
13

Unit rate 40 meters in 60 seconds

Mathematics
1 answer:
gavmur [86]3 years ago
7 0
The answer is .6 repeating.
You might be interested in
3. At the start of summer, Ben has $250 . He takes a summer
earnstyle [38]

Answer:

Week 4

Step-by-step explanation:

Ben has $250 in the beginning.  He saves $150 per week.

y = 150x + 250

Tim has $1,650 in the beginning.  He spends $200 per week.

y = 1650 - 200x

We are trying to find which x-value produces the same y-value for both equations.  You can do this by setting both equations equal to each other.

150x + 250 = 1650 - 200x

(150x + 250) + 200x = (1650 - 200x) + 200x

350x + 250 = 1650

(350x + 250) - 250 = (1650) - 250

350x = 1400

(350x)/350 = (1400)/350

x = 4

By week 4, they will have the same amount of money.

3 0
3 years ago
Check please :D <br> 12345678901234567890
bagirrra123 [75]

Answer: All but one was right

1. 0 (correct)

2. 34 (correct)

3. 398 (correct)

4. -350 (correct)

5. 20 (correct)

6. 200 (wrong)

7. 48 (correct)

8. -1000(correct)

9. 150 (correct)

10. -55 (correct)

Step-by-step explanation:

(2x5)x(9÷3)+4=10x3+4=30+4=34

4(25x8÷2)+3-5=4(200÷2)+3-5=4x100+3-5=400+3-5=403-5=398

-10x20-30(5)=-200-150=-350

5x10-30=50-30=20

4(50-20÷4)+20=4(50-5)+20=4x45+20=180+20=200

3x4(20÷5)=12x4=48

-20(50x2)+5(200)=-20x100+5x200= -2000+1000=-1000

20x5+70-20=100+70-20=170-20=150

-5+10x(-5)==5+-50=-55

6 0
2 years ago
Read 2 more answers
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
3 years ago
At a local preschool there is s as ratio of 3 boys to every 4 girls. If their are 245 total preschoolers enrolled how many are b
Zepler [3.9K]

Number of boys enrolled is 105

<em><u>Solution:</u></em>

Given that, At a local preschool there is s as ratio of 3 boys to every 4 girls

There are 245 total preschoolers

Ratio of boys and girls = 3 : 4

Number of boys : number of girls = 3 : 4

Let the number of boys be 3x

Let the number of girls be 4x

Total number of preschoolers = 245

Therefore,

number of boys + number of girls = 245

3x + 4x = 245

7x = 245

x = 35

Number of boys = 3x = 3(35) = 105

Thus number of boys is 105

3 0
3 years ago
I will give 15 points please help!
N76 [4]
It’s C good luck man(:
6 0
3 years ago
Read 2 more answers
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