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bulgar [2K]
3 years ago
15

PLEASE HELP I don’t understand DONT USE ME FOR POINTS

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

d = 364 feet

Step-by-step explanation:

Given that,

The pressure at depth d is given by :

P=13+\dfrac{8}{13}d

Pressure under water is found to be 237 pounds per square foot

Now, put P = 237 to find d. So,

237=13+\dfrac{8}{13}d\\\\237-13=13+\dfrac{8}{13}d-13\\\\224=\dfrac{8}{13}d\\\\d=\dfrac{224\times 13}{8}\\\\d=364\ ft

So, the depth is equal to 364 feet.

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Which expression is equivalent to 5x - 30
ozzi
Taking out common factor, 5
5x - 30 = 5(x - 6)
5 0
3 years ago
Calculate the mean given the frequency table
DaniilM [7]

Answer:

~15.55 is the mean.

Step-by-step explanation:

The class of frequency is given as 0-9, 10-19 and 20-29.

First of all, let us taken middle value of class:

\dfrac{0+9}{2} = 4.5

\dfrac{10+9}{2} = 14.5

\dfrac{20+9}{2} = 24.5

Formula for mean:

\text{Mean = } \dfrac{\sum (m \times f)}{\sum f}

where f is the frequency

and m is the mean value calculated in above step (4.5, 14.5 and 24.5)

The frequencies are given as:

4.5 -  24

14.5 - 20

24.5 - 32

Putting the values in above formula:

Mean = \dfrac{4.5\times 24+14.5\times 20 +24.5\times 32}{24+20+32}\\\Rightarrow \dfrac{108+290+784}{76}\\\Rightarrow \dfrac{1182}{76} \\\Rightarrow 15.55

Please refer to the attached image that contains the table for calculation of mean.

So, mean = ~15.55

8 0
3 years ago
Pls help w this it’s due at 9
lisabon 2012 [21]
I worked it out on paper so i didn’t have to type hope this helps

3 0
3 years ago
Read 2 more answers
20% of what equals 1581.01
Zepler [3.9K]
If you rewrite this phrase to be an equation, with N representing the missing number, it would be:

20% x N = 1581.01 or 0.2N = 1581.01

This equation basically says 20% of what number equals 1581.01.

To get to the answer, divide both sides by 0.2. -->

0.2N ÷ 0.2 = 1581.01 ÷ 0.2 -->
N = 1581.01/0.2
N = 7905.05


6 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!
Anna35 [415]
4y^2+2=(4y\cdot4y)+2\\
4y^2+2=16y^2+2 \leftarrow \text{not identity}\\\\
4y^2+2=(4y+y)+2\\
4y^2+2=5y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y+y)+2\\
4y^2+2=8y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y\cdot y)+2\\
4y^2+2=4y^2+2 \leftarrow \text{identity}

So it's D.
8 0
4 years ago
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