Answer:
- please mark brainlist please
Step-by-step explanation:
4π/3 radians. Triangle A B C has angles labeled as follows: A, (101x + 2) degrees; B, 34x degrees; C, unlabeled. The measure of ∠BCD is 120°. )
3terms = trinomial (7a^2, 4a, -12)
Degree of each term 2nd, 1st, constant
Largest degree: 2nd
Answer: 2nd degree trinomial
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (:
There are three unknowns in this problem. First, let's assign variables for these unknowns.
Let
x be the amount received by the first friend
y be the amount received by the second friend
z be the amount received by the third friend
Next, we formulate equations for the relationships
x = 4z
z = 4y
x + y + z = <span>$231,000
Solving simultaneously,
4(4y) + y + 4y = </span><span>$231,000
21y = </span><span>$231,000
y = $11,000
z = 4($11,000) = $44,000
x = 4($44,000) = $176,000</span>
The mode is the number that is repeated most often,
here, all the numbers appears just once so we don't have a mode
