X^2+16x+_=(x+_)^2 what are the missing digits?

Mathematics

1 answer:

Eva8 [605]2 years ago

3 0

Answer:

x^2+16x+64=(x+8)^2

Step-by-step explanation:

For the first spot you find the perfect square of the equation

This is found by doing (1/2 16)^2

1/2 16 = 8

8^2 = 64

The second spot is factoring, where you would put half of 16 or the square root of 64

1/2 16 = 8

root 64 = 8

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