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antiseptic1488 [7]
3 years ago
6

As part of a board game, players choose 5 unique symbols from 9 different symbols to create their secret password. How many diff

erent ways can the players create a specific 5 symbol password?
Give your answer in simplest form.
Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer:

15,120

Step-by-step explanation:

For the first symbol, there are 9 options to choose from. Then 8, then 7, and so on. Since each player chooses 5 symbols, they will have a total of 9\cdot 8 \cdot 7 \cdot 6\cdot 5=\boxed{15,120} permutations possible. Since the order of which they choose them matters (as a different order would be a completely different password), it's unnecessary to divide by the number of ways you can rearrange 5 distinct symbols. Therefore, the desired answer is 15,120.

aalyn [17]3 years ago
6 0

Answer:15,120

Step-by-step explanation:

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if a store uses a selling price based markup of 40% and an item cost the store $300 what selling price would the store set for t
kirza4 [7]

Answer:

The selling price would be $420.

Step-by-step explanation:

In order to find the mark up, we need to multiply the amount it originally costs by the percentage it is being marked up.

$300 * 40% = $120

Now that we have the mark up amount, we add it to the original cost to get the sale price.

$300 + $120 = $420

6 0
3 years ago
The total bill for the drinks and pizza comes out to be $17.28. How much should each person pay if they are to share the total b
sleet_krkn [62]

Answer:

5.76

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
This is confusing very confusing for no reason
Aneli [31]

Answer:

I'm pretty sure it's 31

Step-by-step explanation:

perimeter you add all the sides

3 0
2 years ago
The radius of a sphere and of a cylinder are the same. The diameter of the sphere and the height of the cylinder are also the sa
emmasim [6.3K]
First we have to know the formula of the volume f each of the solids, 

<span>V of sphere = 4/3 pi r^3
</span><span>Volume of Cylinder = pi r^2(2r)=2pi r^3
</span><span>Volume of cone = 1/3 pi r^2(r)=1/3 pi r^3
</span>
The surest and easiest way we can answer this is actually assigning values. We first assign values to r hence we would get the volume of the sphere and rest of the solids (cylinder and cone). You then compare your answers to that of the sphere, and you should get your answer. 
4 0
3 years ago
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