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3 years ago

The question is in the pic.

Mathematics

2 answers:

masya89 [10]3 years ago

5 0

Answer:

the answer is $100

because if the bank is loosing 2% they are having to pay $20 bc 0.02 x 1,000= 20, and they are earning 12% they getting 120 bc 0.12 x 1,000 = 120, and 120-20= $100. you have to subtract the $20 because that is what the bank is paying, so it's losing money

vodka [1.7K]3 years ago

4 0

Answer:

$100

$120 in and $20 out

Step-by-step explanation:

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Mia has $40 in a savings account. She will start adding $5 to her account each week. Juan has $15 in a savings account. He will

tensa zangetsu [6.8K]

Y=40+5x
For an example, say Mia wanted to add $5 into her account each week for 2 weeks.
y=40+5(2)
5(2)=10
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2 years ago

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Citrus2011 [14]

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2 years ago

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Men are believed to have a slightly longer average length of short hospital stays than women; 5.2 days versus 4.5 days respectiv

Georgia [21]

Answer:

Since our calculated value is lower than our critical value, $z_{calc}=2.02$ , we have enough evidence to FAIL to reject the null hypothesis at 1% of singificance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

Step-by-step explanation:

1) Data given and notation

$\bar X_{1}=5.2$ represent the mean for group men

$\bar X_{2}=4.5$ represent the mean for group women

Assuming these values for the remaining data:

$\sigma_{1}=1.2$ represent the population standard deviation for the sample men

$\sigma_{2}=1.5$ represent the population standard deviation for the sample women

$n_{1}=32$ sample size for the group men

$n_{2}=30$ sample size for the group women

z would represent the statistic (variable of interest)

$p_v$ represent the p value

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for men it's higher than the mean for women, the system of hypothesis would be:

H0: $\mu_{1} \leq \mu_{2}$

H1: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are higher than 30, and we know the population deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

We have all in order to replace in formula (1) like this:

$z=\frac{5.2-4.5}{\sqrt{\frac{1.2^2}{32}+\frac{1.5^2}{30}}}=2.02$

4) Find the critical value

In order to find the critical value we need to take in count that we are conducting a right tailed test, so we are looking on the normal standard distribution a value that accumulats 0.01 of the area on the right and 0.99 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:

"=NORM.INV(1-0.01,0,1)", and we got $z_{critical}=2.33$

5) Statistical decision

Since our calculated value is lower than our critical value, $z_{calc}=2.02$ , we have enough evidence to FAIL to reject the null hypothesis at 1% of significance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

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3 years ago

The chess club has 16 members and gains a new member every month. the film club has 4 members and gains 4 new members every mont

steposvetlana [31]

<span>For chess club:
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For film club:
y2 = 4 + 4*x where y2 = total number of members after x months.

y1 = y2 when:
16 + x = 4 + 4x
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x = 4 months
Answer: C. 4 months.</span>

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The slope:

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