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Slav-nsk [51]
3 years ago
11

Allie has two cars- a truck and a sedan. Last week, she used 3 gallons of gas in the truck and 5 gallons of gas in the sedan and

drove 181 miles. This week she used 7 gallons of gas in the truck and 6 gallons of gas in the sedan and drove 275 miles. Find the average gas mileage for each vehicle.
Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

sedan = 26 miles/gallon

truck = 17 miles/gallon

Step-by-step explanation:

try to write the text in mathematical format as a system of equations

t=truck s=sedan

\left \{ {{3t+5s=181} \atop {7t+6s=275}} \right.

first equation can be written as

t= (181-5s)/3

we can use it in the second equation and rewrite it as

7[(181-5s)/3]+6s = 275

7(181/3 -5/3s) + 6s = 275

1267/3 - 35/3s + 6s = 275

-35/3s + 18/3s = 275-1267/3

-35/3s + 18/3s = 825/3 - 1267/3

-35s + 18s = 825 -1267

-17s = -442     s = 442/17 = 26 sedan has an average of 26 miles/gallon

we use this value of s in the first equation

3t + 5*26=181      3t=181-130   t= 51/3 = 17 truck has an average of 17 miles/gallon

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Binomial theorem Expand (5 - y)3
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Answer:

(5 - y) ^3 = 125 - 75y + 15y^2 - y^3

Step-by-step explanation:

Binomial expression

1

1. 1

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1. 3. 3. 1 --------power of 3

( 5 - y) ^3

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( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3

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b = -y

( 5 - y) ^2 = ( 5 - y) (5 - y)

= 5( 5 - y) - y(5 - y)

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= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3

Collect the like terms

= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3

= 125 - 75y + 15y^2 - y^3

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