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Slav-nsk [51]
3 years ago
11

Allie has two cars- a truck and a sedan. Last week, she used 3 gallons of gas in the truck and 5 gallons of gas in the sedan and

drove 181 miles. This week she used 7 gallons of gas in the truck and 6 gallons of gas in the sedan and drove 275 miles. Find the average gas mileage for each vehicle.
Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

sedan = 26 miles/gallon

truck = 17 miles/gallon

Step-by-step explanation:

try to write the text in mathematical format as a system of equations

t=truck s=sedan

\left \{ {{3t+5s=181} \atop {7t+6s=275}} \right.

first equation can be written as

t= (181-5s)/3

we can use it in the second equation and rewrite it as

7[(181-5s)/3]+6s = 275

7(181/3 -5/3s) + 6s = 275

1267/3 - 35/3s + 6s = 275

-35/3s + 18/3s = 275-1267/3

-35/3s + 18/3s = 825/3 - 1267/3

-35s + 18s = 825 -1267

-17s = -442     s = 442/17 = 26 sedan has an average of 26 miles/gallon

we use this value of s in the first equation

3t + 5*26=181      3t=181-130   t= 51/3 = 17 truck has an average of 17 miles/gallon

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Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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The parameters are:

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P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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Step-by-step explanation:

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