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3 years ago

6

For the right triangle shown, the lengths of two sides are given. find the third side. leave your answer in simplified, radical

form. a = 8, b = 3

1 answer:

Citrus2011 [14]3 years ago

6 0

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What is the value of the expression (5)"?

AysviL [449]

Answer:5

Step-by-step explanation:(5) Is not changing the value at all so the answer is simply 5

6 0

4 years ago

Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a

kompoz [17]

<u>Answer:</u>

The equation to describe the relationship between Elena distance:

a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

<u>Solution:</u>

Given, Elena bikes 20 minutes each day for exercise.

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,

We know that, distance travelled = speed $\times$ time

a. At a constant speed of 13 miles per hour for the entire 20 minutes

Her speed is 13 miles per hour.

Then, distance D miles = 13 miles per hour $\times$ 20 minutes

$\mathrm{D}=13 \text { miles per hour } \times \frac{20}{60} \text { hours } \rightarrow \mathrm{d}=13 \times \frac{1}{3} \rightarrow \mathrm{d}=4.34 \text { miles approximately. }$

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with 15 mph + distance travelled with 12 mph

$\begin{array}{l}{\mathrm{D}=15 \mathrm{mph} \times 5 \text { minutes }+12 \mathrm{mph} \times 15 \text { minutes }} \\\\ {\mathrm{D}=15 \mathrm{mph} \times \frac{5}{60} \text { hours }+12 \mathrm{mph} \times \frac{15}{60} \text { minutes }} \\\\ {\mathrm{D}=15 \times \frac{1}{12}+12 \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{5}{4}+3 \rightarrow \mathrm{D}=3+1.25 \rightarrow \mathrm{D}=4.25 \mathrm{miles}}\end{array}$

c. At a constant speed of M miles per hour for the first 5 minutes, then at N miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

$D = M mph \times 5 minutes + N mph \times 15 minutes$

$\mathrm{D}=\mathrm{M} \mathrm{mph} \times \frac{5}{60} \text { hours }+\mathrm{N} \mathrm{mph} \times \frac{15}{60} \text { minutes }$

$\mathrm{D}=\mathrm{M} \times \frac{1}{12}+\mathrm{N} \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{N}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{3 N}{12} \rightarrow 12 \mathrm{D}=\mathrm{M}+3 \mathrm{N} \text { miles }$

Hence, a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

8 0

4 years ago

Evaluate C(8,3) <br> C(8,3)=

Arlecino [84]

8 choose 3 = 8!/(3!*(8-3)!) = 8*7*6/(3*2) = 56

7 0

4 years ago

An oblique candle with a volume of 270 cubic centimeters is 18 centimeters tall. The width of the triangular candle base is 5 ce

Scorpion4ik [409]

Volume of the candle:
V = B * h ( where B is the base area and h is the height )
270 = B * 18
B = 270 : 18
B = 15 cm²
B = a * b / 2
B = 5 * b / 2
15 = 2.5 b
b = 15 : 2.5
b = 6 cm
Therefore dimensions of the box are: a = 7cm, b = 6 cm, c = 18 cm.
Answer: B ) 7 by 6 by 18 cm.

6 0

4 years ago

Read 2 more answers

This id hard please help me do this

svlad2 [7]

In this problem, we're going to use the 'PEMDAS' method.

First, we're doing the problem in the parenthesis.
44 - 4 = 40

Next in PEMDAS, we need to do the exponent.
6² = 6 x 6 = 36

Then we would do multiplication, but there is nothing to multiply so we move onto division.
40 / 2 = 20

Now we would add, but there is nothing to add so we move onto subtraction.
20 - 36 = -16

Our final answer would be -16.

Hope this helps!~

7 0

3 years ago

Read 2 more answers