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kow [346]
2 years ago
15

What is the solution to the system of equations below. y = x - 8 y = -2x + 1

Mathematics
1 answer:
klasskru [66]2 years ago
3 0

Answer: x=3 y=-5

Step-by-step explanation:

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8 0
3 years ago
Find the mean median mode and range for the following data 77 60 59 70 89 95
Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

  • 77,60,59,70,89,95

Sort:

  • 59,60,70,77,89,95

To find:

  • Mean
  • Median
  • Mode
  • Range

Mean:

\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}

Sum of all data divides by amount.

\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

\displaystyle \large{\dfrac{x_1+x_2}{2}}

From 59,60,70,77,89,95, since 70 and 77 are in middle:

\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

\displaystyle \large{x_{max}-x_{min}} or highest value - lowest value

Thus:

\displaystyle \large{95-59 = 36}

Therefore, range = 36

7 0
2 years ago
Is " what is the typical amount of rainfall in Canada " a statistical question?​
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Answer:

Yes

Step-by-step explanation:

Yes, the question asks for an average not the rainfall on one specific day, therefore it is a statistical question.

(accidentally answered as a comment)

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3 years ago
(–2) + 6 + 1 = 1 + 6 + (–2) what property is this
jeka94
(–2) + 6 + 1 = 1 + 6 + (–2) is B.Commutative Property
8 0
3 years ago
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