Answer:
Option b is the correct answer
Step-by-step explanation:
The graph in the picture is the graph of a quadratic equation and it takes the shape of a parabola.
The points on the x axis through which the parabola cuts across is used to determine the solution of the quadratic equation.
Looking at the parabola formed from the plotted points, it cuts the x axis at
x = -1 and x= -2
These are the factors of the equation. To get the equation, we multiply the factors.
x= -1, x +1 = 0
x =-2 , x + 2= 0
The equation is (x+1)(x+2)
Expanding the brackets,
x×x + x×2 +1×x + 1×2
= x^2 + 2x + x +2
= x^2 + 3x +2 = 0
Option b is the correct answer
Angles 6 and 8 add up to equal 180, so 2x - 5 + x + 5 = 180. 3x = 180 so x = 60. Angle 3 is alternate interior to angle 6 which is 2(60) - 5 = 115, so angle 3 is also 115
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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B.) because according to the identity property of addition, any number added to zero will remain the same.
