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Zinaida [17]
2 years ago
8

Suppose you know a certain parabola has a vertex of (2, 1) and a y-intercept of 4. By symmetry, you can conclude that the parabo

la contains which of the following points?
a) (4,4)
b) (-2,4)
c) (-2,1)
d) (4,1)
Mathematics
1 answer:
kodGreya [7K]2 years ago
5 0

Answer:

A

Step-by-step explanation:

We are given a parabola with a vertex point of (2, 1) and a <em>y-</em>intercept of <em>y</em> = 4.

And we want to determine another point on the parabola.

Recall that a parabola is symmetric along the axis of symmetry, which is the <em>x-</em>coordinate of the vertex.

Note that since the <em>y-</em>intercept of the parabola is <em>y</em> = 4, this means that a point on our parabola is (0, 4).

To get from (2, 1) to (0, 4), we move two units left and three units up.

Since the parabola is symmetric along axis of symmetry, another point on the parabola will be two units right and three units up. This yields (2 + 2, 1 + 3) or (4, 4).

Our answer is A.

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Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
2 years ago
Read 2 more answers
Write the following polynomial in standard<br> form: <br><br> 4x+3-4x2-10x3
Ne4ueva [31]

Answer:

− 10 x ^3 − 4 x ^2 + 4 x + 3

Step-by-step explanation:

5 0
3 years ago
Elsa took out a 2-year loan to buy a car at 6% simple interest rate if she had to pay264 in interest how much principal did she
mina [271]
I = p * r * t
264 = p * .06 * 2
264 = .12p
Divide both sides by .12
p = $2200
5 0
2 years ago
Find the slope of a line if the points (2,-1) and (5,3) are on the line
Romashka [77]

Answer:

\huge{ \boxed{ \sf{ \frac{4}{3} }}}

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: A \: and \: B}}

\star{ \sf{ \: Let \: a(2,-1)  \: be \: (x1 \:, y1) \: and \: b (5,3)  \: be \: (x2 \:, y2)}}

\underline{ \sf{Finding \: the \: slope \: of \: the \: line}}

\boxed{ \sf{Slope =  \frac{y2 - y1}{x2 - x1} }}

\mapsto{ \sf{Slope =  \frac{3 - ( - 1)}{5 - 2} }}

\mapsto{ \sf{Slope =  \frac{3 + 1}{5 - 2}}}

\mapsto{ \sf{Slope =  \frac{4}{3} }}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

4 0
3 years ago
I don’t know how to solve this.
aev [14]

Answer:

24

Step-by-step explanation:

put 2 over 3 and then simplify it then add the answer with 24

8 0
2 years ago
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