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Likurg_2 [28]
3 years ago
13

Explain how the words term and coefficient are used in talking about the algebraic expression.

Mathematics
1 answer:
cupoosta [38]3 years ago
6 0
<h2><u>Answer:</u></h2>

The <u>algebraic expressions</u> are composed of several elements: Terms, Coefficients, Signs, Variables and Exponents. In this case we will focus on the first two.

<u>The terms</u> are composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).

For example, in the following expression:

2x-3x

We have two terms separated by the negative sign (-):

2x is the first term

-3x is the second term

Now, <u>the coefficients</u> are the numbers that multiply the variable. <u>Note that if this coefficient is one (1) it is omitted .</u>

For example in the following expression, the variable is x:

2x-3x+x

2 is the coefficient of x in the first term

-3 is the coefficient of x in the second term

1 is the coefficient of x in the third term, <u>but is omitted </u>


In order to understand this in a better way, see the figure attached, where the algebraic expression is composed by one term.

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The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

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The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

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Answer:

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