Annie is 3years older than james use j to represent james age

Bezzdna [24]

Answer:

You are only given a Side, an Angle, and then a side. So that is what I would choose. It can't be AA because you weren't given two angles. It can't be SSS because you weren't given 3 sides.

Step-by-step explanation:

3 0

3 years ago

Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

You walk through a used car lot and list the price and model year of each car you see determine whether the two variables are re

Blizzard [7]

Answer:

The narrative in the question can not be described as a function

Step-by-step explanation:

For the purpose of clarity, we will rephrase the question. The key point in the question is to determine if the price and the model are related and if they fit into independent and dependent function.

Moving forward, to properly answer this question, it will be good for us to understand what dependent and independent functions are.

DEPENDENT FUNCTIONS: These are functions or can also be refereed to as variable that represents quantities or values whose parameter depends on how the independent variable is manipulated.

Example:

You are doing job to earn your a salary. For each project you do, you earn $10 dollar. In this case, the dependent variable is the amount of money you earn because the amount of money you earn depends on how many job or project you do.

INDEPENDENT FUNCTIONS: These are functions or can also be refereed to as variable that we have control over in the process of an event therefore, we are at liberty to manipulate it as we so wish as indicated in the dependent variable.

Going back to the narrative of the question, the narrative in the question can not be described as a function because the two identifies variables which are the price and the model years are been altered due to the fact that it is a used car lot so they have both lost their true value or worth. However, some might argue that price here is the independent function or variable while model year is the dependent variable.

5 0

3 years ago

7. An example for using estimation would be:

Aliun [14]

Guessing the number of pennies in a jar

4 0

2 years ago

Read 2 more answers

There are four triangles and 16 squares what is the simplest was ratio of triangles to squares

Elis [28]

1:4 would be the best ratio

5 0

3 years ago