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Vilka [71]
3 years ago
11

PLS HELP

Mathematics
1 answer:
Fed [463]3 years ago
6 0
It would be x is greater then 3 so anything above 3 which would be 5
So the answer is
(4) 5
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\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}&#10;\qquad csc(\theta)=\cfrac{1}{sin(\theta)}&#10;\\\\\\&#10;sin^2(\theta)+cos^2(\theta)=1\\\\&#10;-------------------------------\\\\

\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\&#10;-------------------------------\\\\&#10;\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies &#10;\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1&#10;\\\\\\&#10;\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies &#10;\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}

\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}&#10;\\\\\\&#10;\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}&#10;\\\\\\&#10;\cfrac{1}{sin(\theta )}\implies csc(\theta )
7 0
3 years ago
Find an equation of variation in which y varies directly as x and y=420 when x= 100. Then find the value of y when x=11.
sweet [91]
Let's Simplify X to equal 1 by dividing by 100. then we divide 420 by 100 to get 4.2, so y=4.2 when x=1, we then multiply by each by 11.

y = 46.2
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3 years ago
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