Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
The answer to the question is 52
Answer:
1) There are 15 in it, which means we need to find the 8th. The 8th is 6, which means the median is 6. We then need to find the other quartiles.
8/2=4, which means we need to look at the 4th,5th and 12th,13th.
The first one is FIVE, and the second is SEVEN. Therefore, the FIRST ONE.
2)113
3)37
I think that is D cus you take 10 off
