Please could someone answer this question I would be appreciated
1 answer:
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Answer:
Step-by-step explanation:
Given that for a sample size of 25, sample mean = 102 lbs. and sample std deviation = 10 lbs.
(Right tailed test)
Given that we assume population is normally distributed
Test statistic:
Mean difference = +2
Std error of sample =
t = test statistic = Mean diff/Std error
degree of freedom
Critical value of t = 1.711
Our test statistic >1.71
Accept alternate hypothesis
Because there is significant difference between the test statistic and test statistic lies above critical value.