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3 years ago

Please could someone answer this question I would be appreciated

Mathematics

1 answer:

allochka39001 [22]3 years ago

8 0

Answer:

Step-by-step explanation:

Area = pi r^2

r = 7 cm

pi = 3.14

Area = 3.14 * 7^2

Area = 3.14 * 7*7

Area = 153.86

Area = 153.9 rounded.

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Which of the following expression is equivalent to a+(-b)

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3 years ago

4.5(4 − ) + 36 = 202 − 2.5(3 + 28) Step by Step please

PolarNik [594]

Ok so first off you need to get rid of the clauses in the equation.

So 4.5 ( -4) becomes -18 and -2.5(3+28) becomes -77.5

-18 + 36 = 202 - 77.5

Now you are going to solve the equation.

18 = 122.5

Hope this helped ;),

Casey

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3 years ago

if you vertically stretch the linear parent function, f(x)=x, by a factor of 12, what is the equation of the new function

Vsevolod [243]

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3 years ago

35=3x+14 could anyone help me fast please I also need to show work!

Neporo4naja [7]

Answer:

$\boxed {\tt x=7}$

Step-by-step explanation:

We are given the equation

$35=3x+14$

We want to solve for x, therefore we must isolate x on one side of the equation.

14 is being added to 3x. The inverse of addition is subtraction. Subtract 14 from both sides of the equation.

$35-14=3x+14-14$

$35-14=3x$

$21=3x$

x is being multiplied by 3. The inverse of multiplication is division. Divide both sides of the equation by 3.

$\frac{21}{3} =\frac {3x}{3}$

$\frac{21}{3}=x$

$7=x$

Let's check our solution. Plug 7 in for x and solve.

$35=3x+14$

$35=3(7)+14$

$35=21+14$

$35=35$

This checks out, so we know our solution, x=7 is correct.

8 0

4 years ago

Read 2 more answers

Which is a solution to the equation? (x - 3)(x - 5) = 35 x= -8 x=-5 x=2 x = 10

JulijaS [17]

(x-3)(x-5)=35

Multiply the brackets together

x*x-5*x-3*x-3*5

x^2-8x+15=35

Move +35 to the other side. Sign changes from +35 to -35

x^2-8x+15-35=35-35

x^2-8x-20=0

(x-10)(x+2)=0

x-10=0 x+2=0

Move -10 to the other side. Sign changes from -10 to +10

x-10+10=0+10 x+2-2=0-2

x=10 x=-2

Answer: x=10

4 0

4 years ago

Read 2 more answers

Please could someone answer this question I would be appreciated​

Please could someone answer this question I would be appreciated