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4 years ago

A bonsai tree is 18 inches wide and stands 2 feet tall. What is the ratio of the width of the bonsai to its height?

Mathematics

1 answer:

Afina-wow [57]4 years ago

3 0

Answer:

3:4

Step-by-step explanation:

Before we start to deal with the ratio, we need all lengths in the same units.

The width is 18 inches.

The height is 2 feet.

Let's convert the height to inches. Then we will have both dimensions in the same units, inches.

2 ft * (12 in.)/ft = 24 in.

Now we have:

width = 18 in.

height = 24 in.

ratio of width to height = 18 in. to 24 in. = 18/24 = 3/4 = 3:4

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What is the circumference of a round pizza with an area of 36 square inches ? step by step like can anyone explain to me in word

nadya68 [22]

Answer:

The circumference of the round pizza is 21.26in

Step-by-step explanation:

To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of a circle and we will clear the radius

a = area = 36in²

r = radius

π = 3.14

a = π * r²

we clear r

r = √(a/π)

now we replace the known values

r = √(36in²/3.14)

r = √(11.46in²)

r = 3.385 in

now we use the formula to calculate the circumference of a circle

c = π * 2r

c = 3.14 * 2 * 3.385 in

c = 21.26in

The circumference of the circle is 21.26in

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3 years ago

Anthony brings 4 bags of popcorn to a meeting. The bags of popcorn are all the same size. There are 14 people at the meeting. Ea

spayn [35]

If you divide 4 by 14 you get 0.29 and if you convert it to a fraction you get 29/100

5 0

3 years ago

Hey! I don’t have the energy to do this right now and I’m really hoping one of you could help, please I’m begging. I’ll steal yo

Zolol [24]

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3 apples and 1 banana cause each apple is 1 dollar so just do 1x3=3 and add one banana and it would be 3.50

8 0

3 years ago

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What is the volume of a sphere that has a diameter of 12

posledela

Answer:

V≈904.78

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which of the following could be points on the unit circle: A. (4/3, 4/5) B. (5/13, 12/13)

IRINA_888 [86]

Answer:

Option (2) and (4) are correct.

$(\frac{5}{13},\frac{12}{13} )$ and $(\frac{6}{7},\frac{\sqrt{13}}{7} )$ are points on the unit circle.

Step-by-step explanation:

Given : Some points of circles.

We have to choose which points could be points on the unit circle.

We know, the equation of circle is

$x^2+y^2=r^2$ ..........(1)

where r is radius of circle.

We check each point for x and y values on the equation of circle and see which point gives radius = 1

Thus,

1) $(\frac{4}{3},\frac{4}{5} )$

Put in LHS of (1) , we have,

$(\frac{4}{3})^2+(\frac{4}{5})^2$

Simplify, we have,

$=\frac{16}{9}+\frac{16}{25}$

$=\frac{544}{225}\neq 1$

Thus, $(\frac{4}{3},\frac{4}{5} )$ is not a point on the unit circle.

2) $(\frac{5}{13},\frac{12}{13} )$

Put in LHS of (1) , we have,

$(\frac{5}{13})^2+(\frac{12}{13})^2$

Simplify, we have,

$=\frac{25}{169}+\frac{144}{169}$

$=\frac{169}{169}= 1$

Thus, $(\frac{5}{13},\frac{12}{13} )$ is a point on the unit circle.

3) $(\frac{1}{3},\frac{2}{3} )$

Put in LHS of (1) , we have,

$(\frac{1}{3})^2+(\frac{2}{3})^2$

Simplify, we have,

$=\frac{1}{9}+\frac{4}{9}$

$=\frac{5}{9}\neq 1$

Thus, $(\frac{1}{3},\frac{2}{3} )$ is not a point on the unit circle.

4) $(\frac{6}{7},\frac{\sqrt{13}}{7} )$

Put in LHS of (1) , we have,

$(\frac{6}{7})^2+(\frac{\sqrt{13}}{7})^2$

Simplify, we have,

$=\frac{36}{49}+\frac{13}{49}$

$=\frac{49}{49}= 1$

Thus, $(\frac{6}{7},\frac{\sqrt{13}}{7} )$ is a point on the unit circle.

Thus, $(\frac{5}{13},\frac{12}{13} )$ and $(\frac{6}{7},\frac{\sqrt{13}}{7} )$ are points on the unit circle.

3 0

3 years ago

Read 2 more answers