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ki77a [65]
3 years ago
7

PLZ ANSWER NEED IT ASAP

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

80 square units

Step-by-step explanation:

beep

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Help on #97! Need to know how to work it out using polynomial equations!
olganol [36]
Area = length * width
length = (2 * width) - 1
10 = l*w\\ 10=(2w-1)*w\\ 10=2w^{2}-w\\ 2w^{2}-w-10=0\\ (2w-5)(w+2)=0\\\\ 2w-5=0\\ 2w=5\\ w=\frac{5}{2}=2.5\\ w+2=0\\ w=-2
Since length cannot be negative, w = -2 is not a solution. Thus, \frac{5}{2}~ft is your width.
Since length = 2 * width - 1, plug in width:
l=2(\frac{5}{2})-1\\ l=5-1\\ l=4~ft
7 0
4 years ago
WORTH 100 POINTS!
Karolina [17]

Answer:

Step-by-step explanation:

4. h(x) = 2x^2 + 14x - 60

Step-by-step explanation:

Given that h(x) is a quadratic.

Also, h(3) = h(-10) = 0

(A) h(x) = x^2 - 13x - 30

=> h(3) = 3^2 - 13(3) - 30

=> h(3) = 9 - 39 - 30

=> h(3) = -30 - 30

=> h(3) = -60

=> h(3) ≠ 0

(B) h(x) = x^2 - 7x - 30

=> h(3) = 3^2 - 7(3) - 30

=> h(3) = 9 - 21 - 30

=> h(3) = -12 - 30

=> h(3) = -42

=> h(3) ≠ 0

(C) h(x) = 2x^2 + 26x - 60

=> h(3) = 2(3^2) + 26(3) - 60

=> h(3) = 2(9) + 78 - 60

=> h(3) = 18 + 78 - 60

=> h(3) = 96 - 60

=> h(3) = 36

=> h(3) ≠ 0

(D) h(x) = 2x^2 + 14x - 60

=> h(3) = 2(3^2) + 14(3) - 60

=> h(3) = 2(9) + 42 - 60

=> h(3) = 18 + 42 - 60

=> h(3) = 60 - 60

=> h(3) = 0

And

=> h(-10) = 2(-10)^2 + 14(-10) - 60

=> h(-10) = 2(100) - 140 - 60

=> h(-10) = 200 - 200

=> h(-10) = 0

Clearly we have,

=> h(3) = h(-10) = 0

Hence, the correct option is (D) h(x) = 2x^2 + 14x - 60

4 0
3 years ago
Read 2 more answers
The second term in a geometric sequence is 12. The fourth term in the same sequence is 4/3. What is the common ratio in this seq
aniked [119]
The common ratio in this sequence is 6:2 or 4:3
3 0
3 years ago
Read 2 more answers
Reduce to Standard form : (a) -21/91 (b) 32/(-256)​
sweet [91]

Answer:

a) -3/13

b) -1/8

Step-by-step explanation:

a)  - (21 / 7) / (91 / 7) = 3/13

b) (32 / 32 ) / - (256 / 32) = -1/8​

5 0
3 years ago
Data on pull-off force (pounds) for connectors used in an automobile engine application are as follows:
hjlf

Answer:

a) 75.62

b) 75.2

Step-by-step explanation:

Data provided:

79.9,75.1,78.2,74.1,73.9,75.0,77.6,77.3,73.8,74.6,75.5,74.0,74.7,75.9,72.6,73.8,74.2,78.1,75.4,76.3,75.3,76.2,74.9,78.0,75.1,76.8

Sum = 1966.3

Total number of observations, n = 26

a) Mean is given as:

Mean = \frac{\textup{Sum of all observations}}{\textup{Total number of observations}}

or

Mean = \frac{\textup{1966.3}}{\textup{26}}

or

Mean = 75.62

b) For value that separates the weakest 50% of the connectors i.e median or the 50th percentile

Arranging the data in ascending order:

72.6, 73.8, 73.8, 73.9, 74, 74.1, 74.2, 74.6, 74.7, 74.9, 75, 75.1, 75.1, 75.3, 75.4, 75.5, 75.9, 76.2, 76.3, 76.8, 77.3, 77.6, 78, 78.1, 78.2, 79.9

i = \frac{\textup{n}}{\textup{2}}

or

i = \frac{\textup{26}}{\textup{2}}  = 13

When the number of observations is even the formula for median is:

Median = \frac{\frac{n}{2}+\frac{n+2}{2}}{2}

or

Median = \frac{\frac{26}{2}+\frac{26+2}{2}}{2}

or

Median = \frac{13th+14th}{2}

or

Median = \frac{75.1+75.3}{2}

or

Median = 75.2

7 0
3 years ago
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