3 years ago

SOMEONE HELP ILL KISS U

Mathematics

1 answer:

Ivanshal [37]3 years ago

7 0

Answer:

0, 5x

Step-by-step explanation:

0 in the first box

5x in the second box

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Given the points M (-10, 12) and T(6,8), find the coordinates of the point Q on a directed line segment MT that partitions MT in

uranmaximum [27]

Answer:

$Q(x,y) = (\frac{-18}{5},\frac{52}{5})$

Step-by-step explanation:

Given

$M = (-10,12)$

$T = (6,8)$

$Ratio = 2:3$ at Q

Required

Determine Q

This can be calculated using line ratio formula;

$Q(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})\\$

Where:

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$(x_2,y_2) = (6,8)$

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So, we have:

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$Q(x,y) = (\frac{12 -30}{5},\frac{16 + 36}{5})$

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The coordinates of Q are:

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