Um I assume you're wanting the circumferences of the fences so we have 3 that are all the same size and one that is 3 times as large as any of the others
so here's our equations
3x+y=113.04
y=3x
use substitution
3x+3x=113.04
6x= 113.04
now the question says use 3.14 so I'm thinking you want the answer in terms of pi so first divide 113.04 by 3.14
6x=36pi
x=6pi now substitute that back in for x in one of your equations
y=(3)(6pi)
y=18pi
so the tomatoes carrots and cabbage will all have a circumference of 6pi and the strawberries 18pi
Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
17/20 is 85% in its simplistic form... first put 85/100 and then divide both numerator and denominator by 5.
-0.25 I fell that this is the answer because it is the only one that would make sense
