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Effectus [21]
3 years ago
6

Consider three strings instr1, instr2 and instr3 having only lowercase alphabets. Identity a string outstr, with the smallest po

ssible length such that when strings instr1, outstr and instr2 are concatenated in the same order instr3 becomes a substring of the concatenated string. Print the smallest possible length of (instr1 + outstr - instr2) satisfying the given criteria. Note: The string outstr can also be an empty string Input Format: The first second and third line contain strings instr1instr2 and instr3 respectively. Read the input from the standard input stream. Output Format: Print the smallest possible length of (instr1 + outstr + instr2) satisfying the given criteria. Print the output to the standard output stream You're Explanati CIAR Sample Output Jusuen that when strings instr 1. outstr and instr2 are concatenated in the same order instr3 becomes a substring of the concatenated string. Print the smallest possible length of (instr. outstr - instr2) satisfying the given criteria
Computers and Technology
1 answer:
soldi70 [24.7K]3 years ago
7 0
10 points is nothing to answer this junk just saying
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On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance
Stels [109]

Answer:

#include <stdio.h>

int main()

{

float your_value1, your_value2, your_value3, your_value4, your_value5;

printf("Enter a frequency: ");

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float r = 2.0 / 12;//typing 2.0 so it is treated as float and not int

your_value2 = your_value1 * r * 1; //initial*r*n

your_value3 = your_value1 * r * 2; //initial*r*n

your_value4 = your_value1 * r * 3; //initial*r*n

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printf("%0.2f %0.2f %0.2f %0.2f %0.2f", your_value1, your_value2, your_value3, your_value4, your_value5);

return 0;

}

Explanation:

The purpose of this exercise is to make you understand the difference between float and int. float variables are used when you need decimals in your calculations. int is used when you need integers. The problem in this exercise was the formulation of r. Now r is = 2/12, this means that when we type r as that, the computer assumes that it is an integer and treats it as such. So, it will convert the 0.166667 into 0. To overcome this, all you have to do is type 2.0 instead of 2 alone.

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I have used the function scanf_s instead of scanf simply because my compiler does not work with scanf.

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3 years ago
Which of the following statements is false? Question 4 options: By convention class names begin with an uppercase letter, and me
amm1812

Answer:

Instance variables can be declared anywhere inside a class.

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<em>By convention class names begin with an uppercase letter, and method and variable names begin with a lowercase letter.</em> - True.

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3 years ago
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