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erma4kov [3.2K]
3 years ago
11

legacy application that has hard-coded static IP addresses and is running on an EC2 instance, what is the best failover solution

that allows you to keep the same IP address on a new instance
Computers and Technology
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

Elastic IP address

Explanation:

Elastic IP addresses are static, persistent public IP addresses which can be associated and disassociated with the instance, as required.

This will provide the best failover solution that will keep same IP address on a new instance.

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Answer: by reading the copyright notice on the website where she found the graph.

Explanation: ~Apex~

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Varvara68 [4.7K]

The most effective way to convey your marketing message is to use the channel and media most used by your potential audience.

To discover the most effective channels and means to reach your audience, market research, online traffic study and other strategies to identify the habits and customs of your target market can be carried out.

A marketing message must be written in a way that engages consumers, creates value and desire for your product or service.

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Learn more here:

brainly.com/question/3100288

7 0
2 years ago
Create a program that includes a function called toUpperCamelCase that takes a string (consisting of lowercase words and spaces)
astraxan [27]

Answer:

#include<iostream>

using namespace std;

//method to remove the spaces and convert the first character of each word to uppercase

string

toUpperCameICase (string str)

{

string result;

int i, j;

//loop will continue till end

for (i = 0, j = 0; str[i] != '\0'; i++)

{

 if (i == 0)       //condition to convert the first character into uppercase

  {

  if (str[i] >= 'a' && str[i] <= 'z')   //condition for lowercase

  str[i] = str[i] - 32;   //convert to uppercase

  }

if (str[i] == ' ')   //condition for space

  if (str[i + 1] >= 'a' && str[i + 1] <= 'z')   //condition to check whether the character after space is lowercase or not

  str[i + 1] = str[i + 1] - 32;   //convert into uppercase

if (str[i] != ' ')   //condition for non sppace character

  {

  result = result + str[i];   //append the non space character into string

  }

}

//return the string

return (result);

}

//driver program

int main ()

{

string str;

char ch;

//infinite loop

while (1)

{

fflush (stdin);

//cout<< endl;

getline (cin, str);   //read the string

//print the result

//cout<< endl << "Q";

// cin >> ch; //ask user to continue or not

ch = str[0];

if (ch == 'q' || ch == 'Q')   //is user will enter Q then terminatethe loop

  break;

cout << toUpperCameICase (str);

cout << endl;

}

return 0;

}

8 0
3 years ago
Assume that you have an ArrayList variable named a containing 4 elements, and an object named element that is the correct type t
jonny [76]

Answer:

Option (4) is the correct answer.

Explanation:

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But when the user wants to add some new value to the end of the array list collection then he needs to use the statement--

a.add(element); //where add is a function, element is a value and a is a array list object.

Another option is invalid because--

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  • Option 2 gives a compile-time error because add functions bracts are not closed.
  • Option 3 gives the error because a[4] gives the location of the 5th element of the array but the above question says that a is defined with 4 elements.
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Please help! Game design!
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Answer:

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