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Len [333]
3 years ago
11

11. Robby walks 4 blocks east and 3 blocks north to get to school from his house, as

Mathematics
1 answer:
inna [77]3 years ago
7 0

Answer:

4 plus 3 is 7 so B

Step-by-step explanation:

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Use the method of completing the square to transform the quadratic equation into the equation form (x – p)2 = q. x2 - 12x - 9 =
marissa [1.9K]

Hence, the correct answer is: C) (x - 6)^2 = 45

Further explanation:

Given equation is:

x^2-12x-9=0

We will move the constant term on other side of the equation

x^2-12x=9

To complete the square, we will take the coefficient of x and divide it by 2, as we already know that one term is x.

\frac{12}{2}=6

So, adding (6)^2 on both sides

(x)^2-2.x.6+(6)^2=9+(6)^2\\(x-6)^2=9+36\\(x-6)^2=45

Hence, the correct answer is: C) (x - 6)^2 = 45

Keywords: Quadratic Equation, Solution of equation

Learn more about quadratic equation at:

  • brainly.com/question/4695279
  • brainly.com/question/4703807

#LearnwithBrainly

7 0
3 years ago
(cos x - (sqrt 2)/2)(sec x -1)=0
Darya [45]

(\cos x-\frac{\sqrt{2}}{2})(\sec x-1)=0 [/tex]

=(\cos x-\frac{1}{\sqrt{2}})(\sec x-1)=0 [/tex]

\frac{(\sqrt{2}\cos x-1)}{\sqrt{2}}(\frac{1}{\cos x\ }-1)=0

(Reciprocal Identity)

(\frac{^{\sqrt{2}\\cos  x-1}}{^{\sqrt{2}}})(\frac{1-\cos x}{\cos x})=0

\frac{^{(\sqrt{2}\cos x-1})}{\sqrt{2}}\frac{(1-\cos x)}{\cos x}=0

(\sqrt{2}\cos x-1}){(1-\cos x)}=0 (ZeroProduct Property)

\sqrt{2}\cos x-1=0

\sqrt{2}\cos x=1

\cos x=\frac{1}{\sqrt{2}}

x=\frac{\Pi }{4}

and

1-\cos x=0

\cos x=1

x=0

x=0 and x=\frac{\Pi }{4} are the solutions.

6 0
3 years ago
Read 2 more answers
Suppose the equation ax^2+bx+c=0 has no real solution and a graph of the related function has a vertex that lies in the second q
Veseljchak [2.6K]
If it has no real solutions, that means the graph does not intersect the x axis

since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up

so 'a' must be positive



if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
7 0
3 years ago
For the following relation, find the: a) Reflexive closure b) Symmetric closure c) Transitive closure 2 You may include explanat
Luba_88 [7]

Answer:

Following are the complete solution in the attached file.

Step-by-step explanation:

5 0
3 years ago
Can anyone help me? i dont get it
algol13

Because t is the number of weeks, replace t with 6 in the equation and solve for s.

s = -0.25(6) +4

s = -1.5 +4

s = 2.5

Now replace t with multiples of 6, use 12 and 18:

s =-.25(12) +4 = 1

s-0.25(18) +4 = -0.5

now fins the difference between the time frames:

2.5 - 1 = 1.5

1 - 0.5 = 1.5


The ice melts 1.5 meters every 6 weeks.

5 0
3 years ago
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