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2 years ago

Which are vertical angles? O AFE and BFD O BFC and DFE O AFE and CFD O BFC and EFA

Mathematics

1 answer:

mel-nik [20]2 years ago

3 0

the correct answer is a, because a vertical angle is made of 2 intercepting lines.

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Cost of an airplane flight increase from $250 to $260. What is the percentage increase?

Sedaia [141]

Answer:

Solution given:

Increase percentage= $\frac{260-250}{250}*100$ %

=4%

the percentage increase is 4%.

3 0

2 years ago

Read 2 more answers

Help in this Question

Vadim26 [7]

1 gallon = 16 cups. so 16x3.5=56. so 56 cups

7 0

2 years ago

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A research company claims that no more than 55% of Americans regularly watch FOX News. You decide to test this claim and ask a r

7nadin3 [17]

Answer: z(e) = 2.07

Step-by-step explanation:

1.-The problem is about a test of proportions. As research company claims than no more 55 % of Americans regularly watch Fox News

The null hypothesis is H₀ P₀ ≤ 0.55 from 55%

And the alternative hypothesis is Hₐ Pₐ > .55

Is one tail test

2.-We have to specify significance level we assume our test will be for a significance level α = 5% or α = 0,05

3.-Calculation of z (c) = ?? and z (e) = '??

For z (c) we find in z table the value of z(c) = 1.64

For z (e) = ( P -P₀)/√p₀q₀/n z(e) = 0.05 / √(0.55*0,45)/425 z(e) = 0,05/ 0.02413 z(e) = 2.07

z(e) > z(c) threfore z(e) is in the rejection zone . We reject null hyothesis

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3 years ago

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating

natulia [17]

Answer:

V=25088π vu

Step-by-step explanation:

Because the curves are a function of "y" it is decided to take the axis of rotation as y

, according to the graph 1 the cutoff points of f(y)₁ and f(y)₂ are ±2

f(y)₁ = 7y²-28; f(y)₂=28-7y²

y=0; x=28-0 ⇒ x=28

x=0; 0 = 7y²-28 ⇒ 7y²=28 ⇒ y²= 28/7 =4 ⇒ y=√4 =±2

Knowing that the volume of a solid of revolution V=πR²h, where R²=(r₁-r₂) and h=dy then:

dV=π(7y²-28-(28-7y²))²dy ⇒dV=π(7y²-28-28+7y²)²dy = 4π(7y²-28)²dy

dV=4π(49y⁴-392y²+784)dy integrating on both sides

∫dV=4π∫(49y⁴-392y²+784)dy ⇒ solving ∫(49y⁴-392y²+784)dy

49∫y⁴dy-392∫y²dy+784∫dy =

V=4π( $49\frac{y^{5} }{5}-392\frac{y^{3}}{3}+784y$ ) evaluated -2≤y≤2, or 2(0≤y≤2), also

$V=8\pi(49\frac{2^{5} }{5}-392\frac{2^{3} }{3}+784.2)$ ⇒ V=25088π vu

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3 years ago

Solution set for 6 tan 3x=6

choli [55]

$6\tan3x=6\ \ \ \ |divide\ both\ sides\ by\ 6\\\\\tan3x=1`\\\\3x=\dfrac{\pi}{4}+k\pi\ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=\dfrac{\pi}{12}+\dfrac{k\pi}{3}\ where\ k\in\mathbb{Z}}$

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3 years ago