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natali 33 [55]
3 years ago
12

What is 16 x 2? This is a random question! I want to give away points so be quickkkkk!

Mathematics
2 answers:
Julli [10]3 years ago
5 0

Answer: C.)32 Bestieeeee

Step-by-step explanation:

Anit [1.1K]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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PLS HELP!! Ill mark brainliest!
Artist 52 [7]

Answer:

120 cm^3

Step-by-step explanation:

1. 9 times 5 =45

2. 45 divided by 3 = 15

3. 15 times 8 = 120

8 0
2 years ago
4. Kay and Allen sell cell phones. Last month Kay sold 17 more cell phones than Allen. Together they both sold 117 cell phones.
forsale [732]

Answer:

Allen sold 50 cell phones while Kay sold 67 cell phones.

Step-by-step explanation:

Let the number of cell phones sold by Allen be x. This will imply that the number of cell phones sold by Kay is x + 17.

Furthermore, we are informed that together they sold a total of 117 cell phones. Therefore, we use the following equation to determine the number of cell phones sold by each;

x + x + 17 = 117

2x + 17 = 117

2x = 100

x = 50

Therefore, Allen sold 50 cell phones while Kay sold 67 cell phones.

7 0
3 years ago
Read 2 more answers
No irrational numbers are whole numbers. True or false and why?
Luda [366]
Hi!

Irrational numbers cannot be whole numbers. In order to be a whole number, you cannot have any decimals or fractions. Irrational numbers possess these properties.

Hopefully, this helps! =)
4 0
3 years ago
Read 2 more answers
What is 10% as a decimal?
DiKsa [7]
Hi there!

10% as a decimal is 0.1

To find the decimal of a percentage, just divide the percentage by 100.

10/100 = 1/10 = 0.1

I hope this helps!
6 0
3 years ago
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
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