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Rus_ich [418]
3 years ago
10

Danielle makes the claim that when the polynomial x^2-3x-10 is divided by x-5, the remainder is 0. Use what you have learned abo

ut dividing polynomials to either verify that Danielle is correct or prove that she is incorrect. What arguments would you use to support your claim
Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

<h3>Daniel is correct</h3>

Step-by-step explanation:

Given the polynomial P(x) = x^2-3x-10

To check that the remainder is zero if divided by x - 5, we will first have to equate x - 5 to zero and get x;

x - 5 = 0

x = 5

Then find P(5)

P(5) = 5^2 - 3(5) - 10

P(5) = 25 - 15 - 10

P(5) = 25-25

P(5) = 0

<em>This shows that x - 5 is a factor of the polynomial since P(5) gave us zero according to the factor theorem</em>

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The curved surface area of a right circular cylinder of height 14 cm is 88 cm². ​
Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

<u>GIVEN</u> :

As per given question we have provided that :

  • ➣ Height of cylinder = 14 cm
  • ➣ Curved surface area = 88 cm²

\begin{gathered}\end{gathered}

<u>TO</u><u> </u><u>FIND</u> :

in the provided question we need to find :

  • ➠ Radius of cylinder
  • ➠ Diameter of cylinder

\begin{gathered}\end{gathered}

<u>USING</u><u> </u><u>FORMULAS</u> :

\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}

\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}

  • ➛ Csa = Curved surface area
  • ➛ π = 22/7
  • ➛ r = radius
  • ➛ h = height
  • ➛ d = diameter

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Firstly, finding the radius of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\  \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}}  \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times  \cancel{ 14}}}}  \\  \\  \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\  \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\  \\ \qquad{\longrightarrow{\sf{r =  \frac{88}{88}}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\  \\  \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}

Hence, the diameter of the base of the cylinder is 2 cm.

\rule{300}{2.5}

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