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Yuri [45]
3 years ago
13

What is the percent composition by mass of nitrogen in the compound NH3 (gram-formula mass - 17 g/mol)?

Chemistry
1 answer:
liraira [26]3 years ago
5 0
Answer: d 82%. Your welcome
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4-hydroxypentanal reacts with one equivalent of methanol to form a cyclic acetal.
quester [9]

Answer:

Explanation:

The equation is given as:

CH3CHOHC2H4CHO + CH3OH --> CYCLIC ACETAL + H2O

This above equation is carried out in the presence of a strong acid. There are five mechanisms employed and they are:

Step 1:

Initial formation of the hemiacetal which takes several steps

Step 2:

Addition of a proton. The hemicetal is protonated on the hydroxyl group (-OH group)

Step 3:

As seen a bond is broken to give the H2O molecule and a resonance stabilized cation.

The carbonyl group on the cation is enriched with the oxygen-18 got from the H2O molecule as seen in the mechanism.

Step 4:

An attraction occurs between electrophile and nucleophile i.e the stabilised cation and the lone paids of the methanol.

Step 5:

Finally, a proton (+) is removed from the molecule by a lone pair of electron on the methanol.

Attached are the Steps 1 - 5 mechanism below

4 0
3 years ago
The world's total petroleum reserve is estimated at 2.0 x 10^22 joules La joule (J) is the unit of energy where 1J =1kg m^2/s^2)
mamaluj [8]

Answer:

It will take 1.1\times 10^{2}years to exhaust the supply

Explanation:

We have to apply unitary method to solve this problem.

Divide total petroleum reserve by petroleum consumption in each year to calculate estimated time.

Presently, 1.8\times 10^{20} joules of petroleum are being consumed per year.

Hence, applying unitary method, 2.0\times 10^{22} joules of petroleum can be consumed in \frac{2.0\times 10^{22}}{1.8\times 10^{20}}years=1.1\times 10^{2}years

3 0
3 years ago
Quick Chemistry question, please show work :) 3. If 25.0 mL of a 4.525 M solution of HCl was poured into 112.0 mL of distilled w
fomenos
The total mole number of solutes will not change. So it is 25 * 10^-3 *4.525 mole. And the final volume is 25+112 = 137 mL. So the resulting concentration is mole number / volume=0.8257 M.
7 0
3 years ago
One mole of ar initially at 305 k undergoes an adiabatic expansion against a pressure pexternal = 0 from a volume of 8.5 l to a
PilotLPTM [1.2K]
An adiabatic process is when the system is insulated that no heat is released to the surroundings. For this type of process, we have a derived formula written below:

(T₂/T₁)^C = (V₁/V₂)
where C = Cv/nR

From the complete problem shown in the attached picture, Cv = (3/2)R. Thus,
C= (3/2)/1 mol = 3/2

(T₂/305 K)^(3/2) = (8.5 L/82 L)
Solving for T₂,
<em>T₂ = 67.3 K</em>

3 0
3 years ago
What is generally true about rate over the course of a reaction?. Rate decreases because there are more collisions as the reacti
Vlad1618 [11]
The best answer among the choices listed is the third option. The rate over the course of a reaction <span>decreases because the concentration of reactants decreases. As the concentration of the reactants decreases, there is less particles to form the products therefore less rate.</span>
8 0
3 years ago
Read 2 more answers
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