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Kamila [148]
2 years ago
11

A bag contains counters that are red, black , or green . 1/3 of the counters are red 1/6 of the counters are black There are 15

green counters in the bag. How many black counters are in the bag ?
i’ll give brainliest please help
Mathematics
1 answer:
ad-work [718]2 years ago
7 0

Answer:

5 black counters

Step-by-step explanation:

1/3 to sixths would equal two sixths. The problem already told us three of the siths, meaning the 15 are the other three sixths. Since 3/6 are half of the bag, then multiply 15 by two. Since there are 30 in all, and the bags are in thirds, you devide by three. Since 10 is the 1/3, you divide by 2 (10 by 2) since you multiply 1/3 to get the equivalant of 2/6. There are 5 black ones.

You could've also had done 30 divided by 6 to get 5 which is still the 1/6 of the bag.

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boyakko [2]

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3 years ago
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3 0
2 years ago
Please can someone help me?
Debora [2.8K]
If the perimeters are equal, you can form an equation to find x:
x + x + 12 + x + x + 12 = x + 11 + x + 11 + x + 16
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- 3x
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x = 14
Now you can substitute the x value into the perimeter:
(4 × 14) + 24
56 + 24 = 80 cm

(3 × 14) + 38
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So the perimeter would be 80 cm.
I hope this helps!
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