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Serggg [28]
3 years ago
14

suppose the height of women at a college are approximately normally distributed with a mean of 65 inches

Mathematics
2 answers:
Makovka662 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

kykrilka [37]3 years ago
3 0

Answer:

Height at the 20th ​percentile = 63.74

hope this helps :) plz brainliest if helps

Step-by-step explanation:

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If a real estate agent earns 3% commissions and earned 4,350 on the closing of home what was the price of the home ?
ICE Princess25 [194]

Answer:

145 000

Step-by-step explanation:

4350 = 3%

1% = 1450

100% = 145 000

8 0
2 years ago
The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.
emmasim [6.3K]

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

or,\frac{30 {xy + 20xy}^{2} }{10xy}  = l \\

or, \: l = 3 {x}^{2 - 1}  + 2cm

\boxed{\sf{l = (3x+2)cm}}

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

= \frac{20 {x}^{4} {y}^{2}  }{5 {x}^{3} y}   \\

= 4xy

The product of 3x and 4y = 6xy

= 6x - 4xy

= \boxed{\sf {2xy}}

hope it helped !!!!

7 0
2 years ago
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
Vikki [24]

Answer:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

Step-by-step explanation:

Information given:

n=131 represent the sample size

\hat p=0.81 represent the estimated proportion

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.326

And replacing into the confidence interval formula we got:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

6 0
3 years ago
Find the whole number equal to the fraction below. Enter your answer in the<br> space provided.
zepelin [54]

Answer:

\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}

6/2 ÷ 2/2 = 3/1

3 ÷ 1 = 3

Answer: 3

#CarryOnLearning

4 0
2 years ago
ASAP PLZZ Helllllpppp!!!! Figure N is the result of a transformation on Figure M. Which transformation would accomplish this?
horrorfan [7]

Answer:

b

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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