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Veseljchak [2.6K]
3 years ago
5

Help! Perimeter problem!

Mathematics
1 answer:
love history [14]3 years ago
7 0

Answer:

9.7

Step-by-step explanation:

If you see one side has the exact same numbers on the other side its the same thing from one end to the other

HOPE THIS HELPED

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Solve 4(t+1)=6t-1<br> A) 1 1/2 <br> B) 2 1/2 <br> C) 1 <br> D) 0
-BARSIC- [3]

Answer:

answer is B...2 1/2

Step-by-step explanation:

3 0
3 years ago
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Answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
Ulleksa [173]

Answer:

  • 5x²-2x+7+2x²+6x-9
  • 5x²+2x²-2x+6x+7-9
  • 7x²+4x-2

so, 7x²+4x-2 is yr answer.

hope it helps.

<h3>stay safe healthy and happy.</h3>
8 0
2 years ago
What is perpendicular to y=-1/2x+11
ratelena [41]
You have to find the reciprocal of the gradient - 1/2
And to do that just flip the sign and fraction:
-1/2
1/2
2/1

So the answer is,
Y = 2x + 11
3 0
3 years ago
To show how to do this step by step
Jet001 [13]

Answer:

to do it 5 x 10 x 4 x 5 x 6 x 7 x 3 x 2 3 x 4  x5

Step-by-step explanation:

x 3x 3x 3x3 x4 x4x4 x4x  to the power  of 5 million

3 0
3 years ago
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
2 years ago
Read 2 more answers
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