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katrin2010 [14]
3 years ago
14

If a point is chosen inside the square, what is the probability that it will also be inside the circle?

Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Answer:

79\%

Step-by-step explanation:

The probability that the point is chosen in the circle is equal to the area of the circle divided by the area of the square.

Formulas used:

  • Area of a square with side length s is given by A=s^2
  • Area of a circle with radius r is given by A=r^2\pi

The segment marked as 1 represents not only the radius of the circle, but also half the side length of the square. Therefore, the side length of the square is 2, and we have:

Area of square: A=2^2=4

Area of circle:

A=1^2\pi=\pi

Therefore, the probability that the point will be inside the circle is:

\frac{\pi}{4}=0.78539816339\approx \boxed{79\%}

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Answer:

\huge\purple {\boxed {m\angle FEG =23\degree}}

\huge \orange {\boxed {m\angle FEH=113\degree}}

Step-by-step explanation:

In the given circle, \overline{EG} is diameter and \overline{EH} is tangent at point E.

\therefore \widehat {EFG} is a semicircular arc.

Since, measure of semicircular arc is 180°

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By inscribed angle theorem:

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\huge\purple {\boxed {m\angle FEG =23\degree}}

By tangent secant theorem:

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Since we have given that

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3 years ago
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